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Gelneren [198K]
3 years ago
5

Can someone please help me answer this question ASAP.

Mathematics
1 answer:
WARRIOR [948]3 years ago
7 0

Answer:

(-8, -1)

Step-by-step explanation:

The problem tell us that y = -1.  Plug in this y-value to wherever you see a y in the first equation.  You should be able to solve from there.  Your solution will be (-8,-1).

-2x - 3(-1) = 19

-2x + 3 = 19

-2x = 16

x = -8

For this particular problem, you could have also looked at the answer choices and seen that there was only one answer with the correct y-value.

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Find all real $x$ that satisfy $$(2^x - 4)^3 (4^x - 2)^3 = (4^x 2^x - 6)^3. $$
fomenos

The <em>polynomial-like</em> expression is satisfied by the <em>real</em> value <em>x = 1</em>.

<h3>How to determine the real solution of a polynomial-like expression</h3>

In this question we must apply the concepts of logarithms and <em>algebra</em> properties to solve the <em>entire</em> expression. Initially, we expand the right part of the expression:

(2^{x}-4)^{3}+(4^{x}-2)^{3} = (4^{x}+2^{x}-6)^{3}

(2^{x}-4)^{3} + (4^{x}-2)^{3} = [(2^{x}-4)+(4^{x}-2)]^{3}

(2^{x}-4)^{3}+(4^{x}-2)^{3} = (2^{x}-4)^{3}+3\cdot (2^{x}-4)^{2}\cdot (4^{x}-2)+3\cdot (2^{x}-4)\cdot (4^{x}-2)^{2}+(4^{x}-2)^{3}

3\cdot (2^{x}-4)^{2}\cdot (4^{x}-2)+3\cdot (2^{x}-4)\cdot (4^{x}-2)^{2} = 0

2^{x}-4 + 4^{x}-2 = 0

2^{x}\cdot 2^{x} + 2^{x}-6 = 0

u^{2}+u - 6 = 0

(u+3)\cdot (u-2) = 0

Hence, the roots of the pseudopolynomial are u_{1} = -3 and u_{2} = 2. Only the second one have a real value of <em>x</em>. Hence, we have the following solution:

2^{x} = 2

x\cdot \log 2 = \log 2

x = 1

The <em>polynomial-like</em> expression is satisfied by the <em>real</em> value <em>x = 1</em>. \blacksquare

To learn more on logarithms, we kindly invite to check this verified question: brainly.com/question/24211708

7 0
3 years ago
If f(x)=sqrt of (4sinx+2) then f'(0)=
Fantom [35]
We are given the function <span>f(x)=sqrt of (4sinx+2)  and is asked to find the first derivative of the function when x is equal to zero. 

</span><span>f(x)=sqrt of (4sinx+2) 
f'(x) = 0.5 </span><span>(4sinx+2)  ^ -0.5 * (4cosx) 
</span>f'(0) = 0.5 <span>(4sin0+2)  ^ -0.5 * (4cos0) 
</span>f'(0) = 0.5 <span>(0+2)  ^ -0.5 * (4*1)
</span>f'(x) = 0.5 (2)  ^ -0.5 * (4) 
f'(x) = -.1.65
7 0
4 years ago
The corner store sells a super-size granola bar for $4. How much do eleven super-size granola bars cost?
Elden [556K]

Answer:

44 dollars

Step-by-step explanation:

if one super-size gronola bar costs $4

Then 11 x 4 = 44

6 0
3 years ago
Read 2 more answers
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Olegator [25]

Answer:

Yes

Step-by-step explanation:

It is a function because the x's are not repeating.

The x's are 1, -1, 0, and 2. They are not repeating.

Remember it is a function if the x's don't repeat.

Hope this helps ya!!

5 0
3 years ago
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Kryger [21]

Answer:

0.46 per donut. 46 cents

Step-by-step explanation:

5.49/12=0.4575

Rounding to the nearest cent is about 46 cents per donut.

4 0
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