All categories

3 years ago

Sandy went to 20 baseball games this year. She went to 26 last year. How many baseball games did Sandy go to in total?

Mathematics

2 answers:

ale4655 [162]3 years ago

5 0

Answer:

Step-by-step explanation:

Sergeu [11.5K]3 years ago

5 0

She went to 46 games

20 + 26 = 46

You might be interested in

An expecting mother wants to convert a corner of the nursery in her house into a rectangular playpen by enclosing the corner of

Elena-2011 [213]

10=1+9 1x9=9
=2+8 2x8=16
=3+7 3x7=21
=4+6 4x6=24
=5+5 5x5=25
↑ Left: the possible measurements of the two fences, Right: the possible areas

out of the areas calculated, 25 sq feet is the maximum. :)

Ans: 25 square feet

5 0

3 years ago

V=D/T Solve for T. In two Steps and an Answer.

elena-14-01-66 [18.8K]

Answer:

t=v/d

Step-by-step explanation:

id think that there are two steps

v=d/t

divide D on both sides

v/d=d/t/d

v/d=t

7 0

3 years ago

Read 2 more answers

How do you solve this equation? <br> 8 - 3 (2m-5)

attashe74 [19]

8 + -3 * 2m + (-3)(-5) = 8 + -6m + 15 = 8 + -6m + 15 = (-6m) + (8 + 15 ) = -6m + 23

so the answer is -6m + 23

8 0

3 years ago

Find the standard equation of a sphere that has diameter with the end points given below. (3,-2,4) (7,12,4)

DiKsa [7]

Answer:

The standard equation of the sphere is $(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

Step-by-step explanation:

From the question, the end point are (3,-2,4) and (7,12,4)

Since we know the end points of the diameter, we can determine the center (midpoint of the two end points) of the sphere.

The midpoint can be calculated thus

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

Let the first endpoint be represented as $(x_{1}, y_{1}, z_{1})$ and the second endpoint be $(x_{2}, y_{2}, z_{2})$ .

Hence,

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

Midpoint = $(\frac{3 + 7 }{2}, \frac{-2+12 }{2}, \frac{4 + 4 }{2})$

Midpoint = $(\frac{10 }{2}, \frac{10}{2}, \frac{8 }{2})\\$

Midpoint = $(5, 5, 4)$

This is the center of the sphere.

Now, we will determine the distance (diameter) of the sphere

The distance is given by

$d = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2} + (z_{2}- z_{1})^{2} }$

$d = \sqrt{(7 - 3)^{2} +(12 - -2)^{2} + (4- 4)^{2}$

$d = \sqrt{(4)^{2} +(14)^{2} + (0)^{2}$

$d = \sqrt{16 +196 + 0$

$d =\sqrt{212}$

$d = 2\sqrt{53}$

This is the diameter

To find the radius, r

From $Radius = \frac{Diameter}{2}$

$Radius = \frac{2\sqrt{53} }{2}$

∴ $Radius = \sqrt{53}$

r = $\sqrt{53}$

Now, we can write the standard equation of the sphere since we know the center and the radius

Center of the sphere is $(5, 5, 4)$

Radius of the sphere is $\sqrt{53}$

The equation of a sphere of radius r and center $(h,k,l)$ is given by

$(x-h)^{2} + (y-k)^{2} + (z-l)^{2} = r^{2}$

Hence, the equation of the sphere of radius $\sqrt{53}$ and center $(5, 5, 4)$ is

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = \sqrt{(53} )^{2}$

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

This is the standard equation of the sphere

6 0

3 years ago

Help me please I dont get this

inessss [21]

Answer/Step-by-step explanation:

Area of a rectangle = Length × Width

Width of the large rectangle = a

Length of the large rectangle = (2 + 3 + 4)

Therefore:

Area of the large rectangle = a(2 + 3 + 4)

6 0

3 years ago