1. a b c
2. a b c
3. a b c
4. a b c
5. a b c
then she eliminated 1 choice in 1 and 2, say as follows
1. b c
2. a b
3. a b c
4. a b c
5. a b c
Probability of answering correctly the first 2, and at least 2 or the remaining 3 is
P(answering 1,2 and exactly 2 of 3.4.or 5.)+P(answering 1,2 and also 3,4,5 )
P(answering 1,2 and exactly 2 of 3.4.or 5.)=
P(1,2,3,4 correct, 5 wrong)+P(1,2,3,5 correct, 4 wrong)+P(1,2,4,5 correct, 3 wrong)
also P(1,2,3,4 c, 5w)=P(1,2,3,5 c 4w)=P(1,2,4,5 c 3w )
so
P(answering 1,2 and exactly 2 of 3.4.or 5.)=3*P(1,2,3,4)=3*1/2*1/2*1/3*1/3*2/3=1/4*2/9=2/36=1/18
note: P(1 correct)=1/2
P(2 correct)=1/2
P(3 correct)=1/3
P(4 correct)=1/3
P(5 wrong) = 2/3
P(answering 1,2 and also 3,4,5 )=1/2*1/2*1/3*1/3*1/3=1/108
Ans: P= 1/18+1/108=(6+1)/108=7/108
You would have to divide the categories over the budget. after you divide, you would end up with a decimal, so you to convert it into a percentage, you would simply multiply it by 100.
clothing: 6%
housing: 22%
insurance: 8%
This would result in a biased sample because:
- the survey is surveying elementary kids about a new youth center
most of those kids are more likely than not to want a youth center, so most of them will naturally agree without a doubt for the need of a youth center
- Even the adults at the elementary school are more likely than not to agree with a new youth center because they are teachers and can even benefit from working at the youth center
- in final words the reason why this survey will be biased is because there is no variety in the participants being tested. It is basically just asking teachers she students their preference, excluding the rest of an entire community
please vote my answer brainliest. thanks!
Answer:
−
0.21
Step-by-step explanation:
Convert to a fraction, then convert to a decimal by dividing the numerator by the denominator.
