All categories

2 years ago

The equivalent matrices are .

Mathematics

1 answer:

Burka [1]2 years ago

3 0

Answer:

Step-by-step explanation:

To be equivalent matrices must have the same dimemsions (rank)

dim A= (3,2)

dim B=(2,3)

dim C=(3,2)

dim D=(3,2)

C and D are equivalent since √4=2 !!!

You might be interested in

What is the equation of the midline for the function f (x)? f (t) = 3 cos (x) – 2.5

zaharov [31]

Answer:

y = -2.5

Step-by-step explanation:

For such a problem as this, you can replace all sine or cosine functions with their midline value of 0. Then you have ...

f(x) = 0 -2.5

which simplifies to ...

f(x) = -2.5

You can leave the equation like this, or write it as ...

y = -2.5

_____

Perhaps you can see that the midline is the value of any constant added to a sine or cosine function.

6 0

2 years ago

Help....................

Romashka-Z-Leto [24]

Answer:

The interquartile range is 50.

Step-by-step explanation:

To find our answer we have to first quartile 1 and quartile 3 are equal too. When we look at the plot quartile 1 is equal to 20, quartile 3 is equal to 70 because it is in between 60 and 80. Now to find the interquartile range we will subtract 70 from 20 and we get 50. Therefore, 50 is our answer.

7 0

2 years ago

Read 2 more answers

Matt E. Matic was applying for a job. To determine whether he could handle the job, the personnel manager sent him out to poll 1

Rom4ik [11]

Answer:

No; he did the survey incorrectly.

He surveyed 107 people, not 100.

Step-by-step explanation:

Draw a Venn diagram, when you are presented with information like this;

Presenting it in a Venn diagram would look like what is shown in the pic.

P.S. when drawing a Venn diagram, start with the information regarding individuals who fit in all categories and then work your way to the individuals who fit in just in one category.

8 0

3 years ago

If x^2+1/x^2=3 find the value of x^2/(x^2+1)^2 Express answer as a common fraction. Thanks!!

timama [110]

$x^2+\dfrac1{x^2}=3\implies x^4+1=3x^2\implies x^4-3x^2+1=0$

By the quadratic formula,

$x^2=\dfrac{3\pm\sqrt5}2\implies x^2+1=\dfrac{5\pm\sqrt5}2$

Then

$(x^2+1)^2=\dfrac{25\pm10\sqrt5+5}4=\dfrac{15\pm5\sqrt5}2$

$\implies\dfrac{x^2}{(x^2+1)^2}=\dfrac{\frac{3\pm\sqrt5}2}{\frac{15\pm5\sqrt5}2}=\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}$

Multiply numerator and denominator by the denominator's conjugate:

$\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}\cdot\dfrac{15\mp5\sqrt5}{15\mp5\sqrt5}=\dfrac{45\pm15\sqrt5\mp15\sqrt5-25}{15^2-(5\sqrt5)^2}=\dfrac{20}{100}=\dfrac15$