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maks197457 [2]
3 years ago
9

Simplify: 1/3x(6x - 1) A) 5 3 x B)2x - 1 C)2x - 1 3 D)2x2 - 1 3 x

Mathematics
2 answers:
Nina [5.8K]3 years ago
5 0
Multiplying out the expression, you get
  2x^2 -(1/3)x . . . . . . matches selection D
nata0808 [166]3 years ago
5 0

Answer is <u><em>D </em></u>Use the distributive property to simplify.  


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What is the slope of a line that is perpendicular to the line shown.
sertanlavr [38]

Answer:

3/4

Step-by-step explanation:

First of all, we need to calculate the slope of the line shown. This can be computed as:

m=\frac{\Delta y}{\Delta x}

where

\Delta y = y_2-y_1 is the increment along the y-direction

\Delta x = x_2 - x_1 is the increment along the x-direction

We can choose the following two points to calculate the slope of the line shown:

(-3,2) and (0,-2)

And so, the slope of the line shown is

m=\frac{-2-(2)}{0-(-3)}=-\frac{4}{3}

Two lines are said to be perpendicular if the slope of the first line is the negative reciprocal of the slope of the second line:

m_2 = -\frac{1}{m_1}

Using m_1 = -\frac{4}{3}, we find that a line perpendicular to the line shown should have a slope of

m_2 = -\frac{1}{-4/3}=3/4

5 0
3 years ago
Suppose a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 h
vladimir2022 [97]

A) The probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.

B) The probability the golfer got exactly two holes-in-one during a single game is 8.57%.

C) The probability the golfer got six holes-in-one during a single game is close to 0%.

<h2 /><h2><u>How to determine probabilities</u></h2>

Since a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 holes each, to determine A) what is the probability the golfer got zero or one hole -in-one during a single game, B) what is the probability the golfer got exactly two holes-in-one during a single game, and C) what is the probability the golfer got six holes-in-one during a single game , the following calculations must be performed:

  • 1 - 0.12 = 0.88
  • 0.88 ^ 17 = 0.1138
  • 0.88 ^ 18 = 0.1001

Therefore, the probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.

  • 0.88 ^ 18 - 0.12 ^ 2 = X
  • 0.0857 = X

Therefore, the probability the golfer got exactly two holes-in-one during a single game is 8.57%.

  • 0.12 ^ 6 x 0.88 ^ 12 = X
  • 0.0000000001 = X

Therefore, the probability the golfer got six holes-in-one during a single game is close to 0%.

Learn more about probabilities in brainly.com/question/25273534

3 0
2 years ago
What is the result of 6 / 2(1 + 2) =
castortr0y [4]
1 plus 2 = 3, then u do 6/2 (3), then 3x3 = 9
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2 years ago
Three friends were running at a track as shown here.there postions on the track after 3 sec are shown who is running the slowest
Gennadij [26K]

rEMOVE...NO CONTEXT!

8 0
3 years ago
Need help immediately​
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The answer is 6*square rooted*2
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