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zepelin [54]
2 years ago
10

The millers are going to put a pool in their backyard this summer. The pool will have a depth of 5 feet, and the dimensions show

n in the picture. What will be the total volume of water needed to fill the pool?

Mathematics
1 answer:
erica [24]2 years ago
3 0

Answer:

D : 510 units

Step-by-step explanation:

NOTE:

Something to consider when solving problems like this is to break the large shape down into smaller, more managable shapes. So for this problem, you can break down this irregular shape into two rectangles. This will make solving problems similar to this easier in the future :)

WORK:

I broke down this shape into two rectangles with the following dimensions:

- 12 meters by 5 meters

- 3 meters by 14 meters

You also know that the depth has to be 5 feet (the problem itself did not account for differences in feet and meters, as when I converted the 5 feet to meters and solved that way, none of the answers were correct)

Using this information, you can now solve for the volume of each of the rectangles

12*5*5 = 300 units

3*14*5 = 210 units

Then, you simply add the two volumes together to find the total volume needed to fill the pool which equals

510 units

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Answer:

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Step-by-step explanation:

44 divided by 11 is 4

So Keegan can make 4 bags of candy

4 0
3 years ago
-4x + 2(5x - 6) = 6(x - 2)
Ugo [173]

Answer:

Sorry but this equation gives me 6x-12=6x-12

Step-by-step explanation:

Hope u don't mind me asking but have u tried it out yet and what did you get???

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8 0
2 years ago
The minimum/maximum value of the function y = a(x − 2)(x − 1) occurs at x = d, what is the value of d?
daser333 [38]

Answer:

d=\frac{3}{2}=1.5

Step-by-step explanation:

We have the function:

y=a(x-2)(x-1)

And we want to find x=d for which the minimum/maximum value will occur.

Notice that our function is a quadratic in factored form.

Remember that the minimum/maximum value always occurs at the vertex point.

And remember that the x-coordinate of the vertex is the axis of symmetry.

Since a quadratic is always symmetrical on both sides of its axis of symmetry, a quadratic’s axis of symmetry is the average of the two roots/zeros of the quadratic.

Therefore, the value x=d such that it produces the minimum/maximum value is the average of the two roots.

Our factors are <em>(x-2) </em>and <em>(x-1)</em>.

Therefore, our roots/zeros are <em>x=1, 2</em>.

So, the average of them are:

d=\frac{1+2}{2}=3/2=1.5

Therefore, regardless of the value of <em>a</em>, the minimum/maximum value will occur at <em>x=d=1.5</em>.

Alternative Method:

Of course, we can also expand to confirm our answer. So:

y=a(x^2-2x-x+2)\\y=a(x^2-3x+2)\\y=ax^2-3ax+2a

The x-coordinate of the vertex is still going to be the place where the minimum/maximum is going to occur.

And the formula for the vertex is:

x=-\frac{b}{2a}

So, we will substitute <em>-3a</em> for <em>b</em> and <em>a</em> for <em>a</em>. This yields:

x=-\frac{-3a}{2a}=\frac{3}{2}=1.5

Confirming our answer.

4 0
2 years ago
What is the value of x?
ser-zykov [4K]
X = 20

Isolate the variable by dividing each side by factors that don't contain the variable.
x
=
20
7 0
2 years ago
Read 2 more answers
8xy-3y^2+5x^2-7xy+12x^2-2y^2-3xy+8y^2
BabaBlast [244]
 8xy-7xy-3xy-3y²-2y²+8y²+5x²+12x²
then simplify by combining like terms -2xy+3y²+17x²
6 0
3 years ago
Read 2 more answers
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