Part A
Given that

Then,

For

, then

Thus,

For

, we have

Part B
Recall that from part A,

Now, at initial position, t = 0 and

, thus we have

and when the velocity drops to half its value,

and

Thus,

Thus, the distance the particle moved from its initial position to when its velocity drops to half its initial value is given by
Answer:
15.4 (rounded to 1dp)
Step-by-step explanation:
You multiply 1 1/2 by 5 (because you give it to them 5 times a day) and you get 7 1/2 then you have to multiply that by 4 (because you’re calculating how much over 4 days) and you get 30oz .