The solution is given below:
<h3>What is price index?</h3>
An index number expressing the level of a group of commodity prices relative to the level of the prices of the same commodities during an arbitrarily chosen base period and used to indicate changes in the level of prices from one period to another.
Given:
Comm. p0 q0 p1 q1 p0q0 p1q0 p1q1 p0q1
A 25 750 30 960 18750 750 28800 24000
B 30 450 25 550 13500 750 13750 16500
C 5 250 6 360 1250 30 2160 1800
D 6 90 7 210 540 42 1470 1260
E 10 140 10 190 1400 100 1900 1900
F 4 48 5 65 192 240 365 260
Now,
p0q0 = 35632
p1q0 = 1912
p1q1 = 48445
p0q1= 45720
1) P01(L) = p1q0/p0q0 * 100
= 5.36
2) P01(L) = p1q1/p0q1 * 100
= 105.96
Dorbish- Bowley
= 5.36+ 105.96/2
=55.66
Marshall- Edgeworth
= 1912+ 48445/35632 + 45720
= 50357/ 81352
= 0.619 *100= 61.9
Fisher's price index
=( 5.36 * 105.96 )^ 0.5
=23.831
Learn more about price index here:
brainly.com/question/14184515
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Step-by-step explanation:
I use desmos . com so it's easier.
A) 1.29
B) 0.91
C) 0.97
D) 1.05
Good Luck!
Answer:
1150
Step-by-step explanation:
a2=a1+d
d=4
sn=(n/2)(2a1+(n-1)d)
s25=(25/2)(2×(-2)+24×4)=25×46=
1150
Answer/Step-by-step explanation:
To find out the mistake of the student, let's find the min, max, median, Q1 and Q3, which make up the 5 important values that are represented in a box plot.
Given, {2, 3, 5, 6, 10, 14, 15},
Minimum value = 2
Median = middle data point = 6
Q1 = 3 (the middle value of the lower part of the data set before the median)
Q3 = 14 (middle value of the upper part of the data set after the median)
Maximum value = 15
If we examine the diagram the student created, you will observe that he plotted the median wrongly. The median, which is represented by the vertical line that divides the box, ought to be at 6 NOT 10.
See the attachment below for the correct box plot.
Answer:
Lol
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