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Dmitrij [34]
3 years ago
7

Am I doing this right? I circled the answer that I got. We’re supposed to use division to solve the questions.. please let me kn

ow if I’m doing this right!

Mathematics
1 answer:
kifflom [539]3 years ago
3 0
Both of your answers are correct!

so yes youre doing it right
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Divide the following polynomial using synthetic division, then place the answer in the proper location on the grid. Write answer
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An engineer is designing a storage compartment in a spacecraft .The compartment must be 2 meters longer than it is wide, and its
serg [7]

Answer:

Let x be the width of the compartment,

Then according to the question,

The length of the compartment = x + 2

And the depth of the compartment = x -1

Thus, the volume of the compartment,  V = (x+2)x(x-1) = x^3 + x^2 - 2x

But, the volume of the compartment must be 8 cubic meters.

⇒ x^3 + x^2 - 2x = 8

⇒ x^3 + x^2 - 2x - 8=0

⇒ (x-2)(x^2+3x+4)=0

If x-2=0\implies x = 2 and if  x^2+3x+4=0\implies x = \text{complex number}

But, width can not be the complex number.

Therefore, width of the compartment = 2 meter.

Length of the compartment = 2 + 2 = 4 meter.

And, Depth of the compartment = 2 - 1 = 1 meter.

Since, the function that shows the volume of the compartment is,

V(x) = x^3 + x^2 - 2x

When we lot the graph of that function we found,

V(x) is maximum for infinite.

But width can not infinite,

Therefore, the maximum value of V(x) will be 8.




8 0
4 years ago
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Bottles of a popular cola drink are supposed to contain 300 ml of cola. There is some variation from bottle to bottle because th
Ksju [112]

Answer:

We conclude that the mean contents of cola bottles is more than or equal to the advertised 300 ml.

Step-by-step explanation:

We are given that Bottles of a popular cola drink are supposed to contain 300 ml of cola. The distribution of the contents is normal with standard deviation of 3 ml.

A student who suspects that the bottler is under-filling measures the contents of six bottles. The results are: 299.4, 297.7, 301.0, 298.9, 300.2, 297.0

<u><em>Let </em></u>\mu<u><em> = mean contents of cola bottles.</em></u>

SO, Null Hypothesis, H_0 : \mu \geq  300 ml   {means that the mean contents of cola bottles is more than or equal to the advertised 300 ml}

Alternate Hypothesis, H_A : \mu < 300 ml   {means that the mean contents of cola bottles is less than the advertised 300 ml}

The test statistics that will be used here is <u>One-sample z test statistics</u> as we know about the population standard deviation;

                       T.S.  = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean contents of cola bottle = \frac{\sum X}{n} = 299.03 ml

            \sigma = population standard deviation = 3 ml

            n = sample of bottles = 6

So, <em><u>test statistics</u></em>  =  \frac{299.03-300}{\frac{3}{\sqrt{6} } }     

                               =  -0.792

<em>Now at 5% significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is more than the critical value of z as -0.792 > -1.6449, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>

Therefore, we conclude that the mean contents of cola bottles is more than or equal to the advertised 300 ml.

8 0
4 years ago
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