Answer:
(x+7)^2 + (y+4)^2 = 6^2
or
(x+7)^2 + (y+4)^2 = 36
Step-by-step explanation:
We can write the equation of a circle in the form
(x-h)^2 + (y-k)^2 = r^2
Where (h,k) is the center and r is the radius
(x--7)^2 + (y--4)^2 = 6^2
(x+7)^2 + (y+4)^2 = 6^2
or
(x+7)^2 + (y+4)^2 = 36
Step 2 should be:
-6x -9x = - 8 - 2
So answer is the last one
In step 2, Ben did not maintain the equality of the equation
The three angles of a triangle always have to add up to 180degrees. If one of the angles is obtuse(which means it is bigger than 90degrees), the other two angles will both always be less than 90 degrees.
The fact that the healthy school lunch has a higher price than the current lunch means that it has a <u>higher economic cost.</u>
<h3>What is an economic cost?</h3><h3 />
An economic cost in this scenario, is the increased cost that comes with a commodity having greater perceived value.
A healthy school lunch will help a person stay healthy which is why it has more value than the current lunch. This is the reason for its higher price.
Find out more on economic cost at brainly.com/question/902188.
#SPJ1
Step-by-step explanation:
Please find the attachment.
We have been given a circle and we are asked to prove that TO is the bisector of angle BTC.
To prove that TO is bisector of angle BTC, we just need to prove that angle BTO is congruent to angle CTO.
We have been given that TB and Tc are tangents to circle O. Since we know that tangents that meet at same point are equal in length.
Since O is the center of our given circle, so OB and OC will be the radii of our given circle.
Since all the points on a circle are equidistant from the center and radius of circle has one one endpoint on the circle and one at the center, so all radii of a circle are congruent.
We also know that a tangent to a circle is perpendicular to the radius drawn to the point of tangency. As OB and OC are radii and TB and TC are tangents of our given circle,
We can see in our triangles TBO and TCO that,
Therefore, by SAS congruence .
So by corresponding parts of congruent triangles are congruent , therefore, TO is the bisector of .