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3 years ago

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Mathematics

1 answer:

Hitman42 [59]3 years ago

8 0

Answer:

answer of this question is = m⁹n⁶p¹⁵

and plz mark my answer as brainlist if it help you out with this question and plz vote me .....

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Select the correct answer. The grounds crew at a college is installing a path around a pond on campus as shown. What is the peri

olchik [2.2K]

Answer:

Step-by-step explanation:

You are combining like terms.

1.) find all of the #x³ and there is only one and that is -x³ so that limits the problem to B or D.

2.) now you find all of the #x² and there are three of them being 10x², -x², and 4x². Now that you have identified them you will add them together to get a sum of 13x²

you don't have to do anymore of the question because D does not have 13x² so it is B.

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3 years ago

A student is running a 3-kilometer race. He runs 1 kilometer every 2 minutes. Select the function that describes his distance fr

Ronch [10]

Answer:x - number of minutes;

f ( x ) - the distance from the finish line.

x : 0 2 4 6

f ( x ) : 3 2 1 0

f ( x ) = 3 - x/2

Answer: B ) f ( x ) = -1/2 x + 3

Step-by-step explanation:

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3 years ago

Read 2 more answers

Vasco needs to know the area of the four-pointed star

Rama09 [41]

Answer:

Step-by-step explanation:

Find the area of the base

The base is a square.

The formula is Area = s^2

s = 1.5

Area = 1.5^2

Area = 2.25 sq cm.

Area of 1 triangle

h = 2.4

b = 1.5

Area = 1/2 * b * h

Area = 1/2 * 1.5 * 2.4

Area = 1.8 cm^2

Area of 4 triangles

Area = 4 * area of 1 triangle

Area = 4 * 1.8

Area = 7.2

Total Area = 2.25 + 7.2 = 9.45 cm^2

7 0

3 years ago

Please answer right away!!!

liraira [26]

Answer:

22.9m

Step-by-step explanation:

Using Pythagorean theorem, we can get two equations using the angles.

From Point A:

∠A = 20°

AB = 20m

From Point B:

∠B = 29°

BD = x

What we are looking for is the opposite side of each right triangle, each person makes because we have one adjacent side. We also know that both opposite sides will be equal.

So we use this formula for both point of views:

$Tan\theta=\dfrac{Opposite}{adjacent}$

Where:

Opposite = height of the building

Adjacent = distance from the building

We are looking for the opposite side so we can tweak our formula to get an equation for the height

$height=(Tan\theta)(distance)$

Using our given, we can solve for the distance of point B to D:

$(Tan20)(20+x) = (Tan29)(x)\\\\(0.3640)(20+x) = (0.5543)(x)\\\\\dfrac{(7.28+0.3640x)}{0.5543}=x\\\\13.1337 + 0.6567x = x\\\\13.1337 = x - 0.6567x\\\\13.1337 = 0.3433x\\\\\dfrac{13.1337}{0.3433}=x\\\\38.2572 = x$

The distance of point B to D is 38.2572 m.

Now that we know the distance of BD we can solve for the height of the building using only the given from point B.

$height=(Tan\theta)(distance)$

$height=(Tan29)(38.2572m)$

$height=(0.5543)(38.2572m)$

$height=21.21m$

But this is only the height from the line of sight. To get the height of the building from the ground, we just add the height of the viewer, which is 1.7m.

21.21m + 1.7m = 22.91m

The closest answer is: 22.91 m

8 0

4 years ago

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nadya68 [22]

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4 0

3 years ago