Answer:
a) see below
b) 40x20 meters
Step-by-step explanation:
Write down what you know:
- The area of the enclosure is length*width, so

- The length of the fencing is 80 meters, so

Now we have to combine these two equations above, and get rid of y in the process.
First rewrite the second as:

Then substitute for y in the first:

b) To maximize A, find the zero of the first derivative:

So y = (80-40)/2 = 20 meters.
Answer:
Length: 12
Width: 2
Area: 24
Step-by-step explanation:
We first find the points of C and D to find the length.
C: (-4,-5)
D: (2,-3)
The distance is 2
.
Now for the height.
A: (2,9)
D: (2,-3)
The distance is 12.
Area: 2
×12 = 24
Answer:
‐15−8= ‐15 + -8
‐15−(‐8)= ‐15 + 8
Step-by-step explanation:
‐15−8 = -23
‐15 + -8 = -23
‐15−(‐8) = -7
-15+8 = -7