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snow_tiger [21]
3 years ago
9

3. A savings account has a 3% interest rate. (a) Complete the ratio table shown. Show your work. Deposit ($) 100 50 300 Interest

($) 3 12 6 36 (b) How much more interest would you have if you deposited $200 than if you deposited $150? Show your work.
Mathematics
1 answer:
Vladimir [108]3 years ago
6 0

Answer:

Wait what

Step-by-step explanation:

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Is this what you needed?

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2 years ago
There are not asymptotes for the parent function<br> f (x) =1/x <br> True<br> False
Georgia [21]

Answer:

True

Step-by-step explanation:

the parent function f(x) = 1/x has a vertical asymptote at x = 0 and a horizontal asymptote at y = 0

4 0
3 years ago
Only 3/5 of the University students wanted to become math teachers if 3500 did not want to become math teachers how many univers
Tasya [4]

Answer:

8750

Explanation:

There are 5/5 math teachers in the university. 3/5 of them did not want to become math teachers which means 2/5 of the math teachers is equal to 3500.

3500=2/5

divide 3500 by 2 to get 1/5 of the math teachers.

3550/2=1750

1750 is 1/5 of the math teachers.

multiply 1750 by 5 to get 5/5 of the math teachers

1750*5= 8750

3 0
2 years ago
Two rectangles are similar. If the height of the first rectangle is 3 inches, and the height of the second rectangle is 9 inches
scoundrel [369]
Three times longer than the second one.
6 0
3 years ago
3. Using the sample size of 800 and the proportion 0.47, calculate the margin of error associated with the estimate of the propo
salantis [7]

Answer:

ME=1.96\sqrt{\frac{0.47 (1-0.47)}{800}}=0.0346  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

We assume for this case a confidence level of 95%. In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And if we replace the values obtained we got this:

ME=1.96\sqrt{\frac{0.47 (1-0.47)}{800}}=0.0346  

6 0
2 years ago
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