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2 years ago

6

In a sample of 60 diners at a restaurant, 12 had ordered an appetizer. If the restaurant serves 800 diners each day, how many ar

e likely to order an appetizer?

2 answers:

ZanzabumX [31]2 years ago

7 0

There are 160 people who are likely to order an appetizer.

In order to find this, you first divide 60 by 12 to get 5. This means 1 out of every 5 people buys an appetizer, so to find how many out of 800 buy an appetizer, you divide 800 by 5. Thus getting 160 as an answer.

I hope this helps!

san4es73 [151]2 years ago

5 0

If im correct i think it should be 160 because i divided 60 by 12 and got 5 the divided 800 by 5 and got 160.

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Which of the following represents the difference between ten and a number is the sum of eight and a number"?

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Answer:

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Step-by-step explanation:

The difference between 10 and a number is (10 -N).

The sum of 8 and a number is (8 +N).

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10 -N = 8 +N

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Mitchell walked 5/12 of a mile in 1/2 of an hour. At this rate, how far could Mitchell walk in 1 hour?

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$2 \times \frac{1}{2} hour = 1hour \\$

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Y=-1/3x^2-4x-5 in vertex form

grigory [225]

Answer:

$Y=-\frac{1}{3}(x+6)^2+7$ [Vertex form]

Step-by-step explanation:

Given function:

$Y=-\frac{1}{3}x^2-4x-5$

We need to find the vertex form which is.,

$y=a(x-h)^2+k$

where $(h,k)$ represents the co-ordinates of vertex.

We apply completing square method to do so.

We have

$Y=-\frac{1}{3}x^2-4x-5$

First of all we make sure that the leading co-efficient is =1.

In order to make the leading co-efficient is =1, we multiply each term with -3.

$-3\times Y=-3\times\frac{1}{3}x^2-(-3)\times4x-(-3)\times 5$

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Isolating $x^2$ and $x$ terms on one side.

Subtracting both sides by 15.

$-3Y-15=x^2+12x-15-15$

$-3Y-15=x^2+12x$

In order to make the right side a perfect square trinomial, we will take half of the co-efficient of $x$ term, square it and add it both sides side.

square of half of the co-efficient of $x$ term = $(\frac{1}{2}\times 12)^2=(6)^2=36$

Adding 36 to both sides.

$-3Y-15+36=x^2+12x+36$

$-3Y+21=x^2+12x+36$

Since $x^2+12x+36$ is a perfect square of $(x+6)$ , so, we can write as:

$-3Y+21=(x+6)^2$

Subtracting 21 to both sides:

$-3Y+21-21=(x+6)^2-21$

$-3Y=(x+6)^2-21$

Dividing both sides by -3.

$\frac{-3Y}{-3}=\frac{(x+6)^2}{-3}-\frac{21}{-3}$

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Answer:

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Step-by-step explanation:

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