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stepladder [879]
3 years ago
7

A giant pie is created in an attempt to break a world record for baking. The pie is shown below: A circle is shown with a centra

l angle marked 37 degrees and the diameter marked 35 feet. What is the area of the slice of pie that was cut, rounded to the nearest hundredth?
Mathematics
2 answers:
AfilCa [17]3 years ago
6 0

Answer:

98.88 ft^2  to nearest hundredth

Step-by-step explanation:

Area of slice = (37/360)  *  pi * 17.5^2    ( 17.5 = radius ( half diameter of 35))

=   98.88 ft^2


timofeeve [1]3 years ago
4 0

Answer:

98.88

Step-by-step explanation:


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Step-by-step explanation:

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Given that (-9,-1) is on the graph of f(x) find the corresponding point for the function f(x+3).
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3 years ago
Suppose that insurance companies did a survey. They randomly surveyed 400 drivers and found that 320 claimed they always buckle
nirvana33 [79]

Answer:

i) ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

And replacing we got:

ME= 1.96*\sqrt{\frac{0.8 (1-0.8)}{400}} =0.0392

ii) Lower = 0.8-0.0392= 0.7608

Upper = 0.8 +0.0392= 0.8392

Step-by-step explanation:

Notation and definitions

X=320 number of people that claimed always buckle up.

n=400 random sample taken

\hat p=\frac{320}{400}=0.8 estimated proportion of people that claimed always buckle up

p true population proportion of people that claimed always buckle up

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

Part i

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

The margin of error is given by:

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

And replacing we got:

ME= 1.96*\sqrt{\frac{0.8 (1-0.8)}{400}} =0.0392

Part ii

And the confidence interval would be given by:

Lower = 0.8-0.0392= 0.7608

Upper = 0.8 +0.0392= 0.8392

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