Which congruence theorem can be used to prove ABR = RCA?
1 answer:
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The equation for the linear function whose graph contains the points (-1, -2) and (3, 10) is y = 3x + 1
<h3><u>Solution:</u></h3>Given that linear function whose graph contains the points (-1, -2) and (3, 10)
We have to find the equation of line
Any function of the form f (x) = m x + b, where m is not equal to 0 is called a linear function
So let us use the slope intercept form
<em><u>The slope intercept form is given as:</u></em>
y = mx + c
Where "m" is the slope of line and "c" is the y - intercept
Let us first find slope of line containing points (-1, -2) and (3, 10)
<em><u>The slope of line is given as:</u></em>
Thus the slope of line is "m" = 3
Substitute m = 3 and (x, y) = (-1, -2) in y = mx + c
-2 = 3(-1) + c
-2 = -3 + c
c = -2 + 3 = 1
Now substitute c = 1 and m = 3 in slope intercept form to get equation of line
y = 3x + 1
Thus the equation for the linear function is found out
Answer:
42x-24y-5
Step-by-step explanation:
We can start by using the distributive property.
This will help us rewrite the expression, since the terms in the parentheses can't be combined.
I'll attach an image to better explain this.
When using it, we'll get:
6*7x+6*-4y-5
Simplify.
42x-24y-5
This is our final answer since there are no like terms that can be combined.
