Answer:
- a(x) = 20 + 0.60x
- domain [0, 50]; range [20, 50]
- maybe
Step-by-step explanation:
a) If x liters are removed from a container with a volume of 50 L, the amount remaining in the container is (50 -x) liters. Of that amount, 40% is acid, so the acid in the container before any more is added will be ...
0.40 × (50 -x)
The x liters are replaced with 100% acid, so the amount of acid that was added to the container is ...
1.00 × (x)
Then after the remove/replace operation, the total amount of acid in the container is ...
a(x) = 0.40(50 -x) +1.00(x)
a(x) = 20 +0.60x . . . . . liters of acid in the final mixture
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b) The quantity removed cannot be less than zero, nor can it be more than 50 liters. The useful domain of the function is 0 ≤ x ≤ 50. (liters)
The associated range is 20 ≤ a ≤ 50. (liters)
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c) As we found in part b, the amount of acid in the final mixture may range from 20 liters to 50 liters. So, the percentage of acid in the final mix will range from 20/50 = 40% to 50/50 = 100%. The mixture could be 50% acid, but is not necessarily.
Answer:
8
Step-by-step explanation:
if you wrote out A(n) correctly than the answer is 8
Answer:
yes
Step-by-step explanation:
Answer:
2.5
Step-by-step explanation:
Answer:
The 5 rational are 91/150 , 92/150 , 93/150 , 94/150 , 95/150
Step-by-step explanation:
We have to fine 5 rational numbers between
3/5 and 2/3
First we have to make the denominator same
3/5= 3/5 ×3/3 = 9/15 =9/15×10/10 =90/150
2/3 = 2/3×5/5 = 10/15 = 10/15×10/10 = 100/150
The 5 rational numbers are
91/150 , 92/150 , 93/150 , 94/150 , 95/150
hope this helps :)
