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mars1129 [50]
3 years ago
5

Th e NCAA recommends that a competition diving pool intended for use with two 1-m springboards and two 3-m springboards, in addi

tion to diving platforms set at 5 m, 7.5 m, and 10 m above the water, have a width of 75 ft 1 in., a length of 60 ft, and a minimum water depth of 14 ft 10 in. What is the minimum volume of water such a pool would hold in cubic yards, to the nearest whole number?
Mathematics
1 answer:
Anna [14]3 years ago
6 0

Answer:

The volume of the swimming pool is approximately 2475 yd³ to the nearest whole number

Step-by-step explanation:

The given information are;

The width of the swimming pool = 75 ft. 1 in.

The length of swimming pool = 60 ft.

The depth of the swimming pool = 14 ft. 10 in.

Therefore;

The volume of the swimming pool = Width × Length × Depth

The volume of the swimming pool = 75 ft. 1 in. × 60 ft. × 14 ft. 10 in.

The volume of the swimming pool = 901 in. × 720 in. × 178 in. = 115472160 in.³

1 in.³ = 2.14335 × 10⁻⁵ yd³

∴ 115472160 in.³ = 115472160 in.³  × 2.14335 × 10⁻⁵ yd³/in³ ≈ 2474.969 yd³

Which gives;

The volume of the swimming pool ≈ 2475 yd³ to the nearest whole number.

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Question is down below
Bingel [31]

This is a great question!

To determine the probability with which two sweets are not the same, you would have to subtract the probability with which two sweets are the same from 1. That would only be possible if she chose 2 liquorice sweets, 5 mint sweets and 3 humburgs -

Probability( 2 Liquorice) = 12 / 20 * 11 / 19

As you can see, the first time you were to choose a Liquorice, there would be 12 out of the 20 sweets present. After taking that out however, there would be respectively 11 Liquorice out of 19 remaining. Apply the same concept to each of the other sweets -

Probability(2 Mint ) = 5 / 20 * 4 / 19,\\Probability( 2 Humbugs ) =  3/20 * 2/19

____

Calculate the probability of drawing 2 of each, add them together and subtract from one to determine the probability that two sweets will not be the same type of sweet!

1-\left(\frac{132}{380}+\frac{20}{380}+\frac{6}{380}\right) =\\\frac{111}{190}

<u><em>Thus, the probability should be 111 / 190</em></u>

5 0
3 years ago
¿Qué número sigue? <br> 1; 1; 3; 15; 105;
Firlakuza [10]

Answer:

307

Step-by-step explanation:

free points

6 0
3 years ago
What is the area of the trapezoid shown? (1) angle a = 120 degrees (2) the perimeter of trapezoid abcd = 36?
Maurinko [17]
Not enough information to solve this
4 0
3 years ago
2x+4-3x=-11 what is the answer
Pie
You want the xs and the numbers on different sides. 
2x-3x=-11-4
-x=-15
divide x by a -1
x=15
8 0
3 years ago
Read 2 more answers
There are 4 consecutive odd integers that sum to 120.
allsm [11]

Answer:

27, 29, 31, 33

Step-by-step explanation:

Let x represent the smallest odd integer then...

x+2 represents the second

x+4 represents the third

x+6 represents the fourth

We can use this to set up an equation:

x+x+2+x+4+x+6=120

Combine like terms

4x+12=120

Subtract 12 from both sides

4x=108

Divide both sides by 2

x=27

The integers are 27, 29, 31, 33

4 0
2 years ago
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