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3 years ago

9

Solve the problem down below: ty :P

1 answer:

AVprozaik [17]3 years ago

5 0

Answer:

the correct answer is1/4

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seraphim [82]

Answer:

Is this a go ogle meet

Step-by-step explanation:

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3 years ago

Solve the equation 1/2(16x – 6) = 2.

Lorico [155]

Answer:

x = 0.625 or 5/8

Step-by-step explanation:

1/2(16x-6) = 2

8x - 3 = 3

8x = 3 + 3

8x/8 = 9/8

x = 0.625

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6 0

3 years ago

F(x) = 2x^2-x-1<br> if f(x) = -1, what is x? What point(s) are on the graph<br> of f ?

Elina [12.6K]

Answer:

x = 0, x = 0.5 or 1/2 The points on the graph are ( -1/2 or -0.5,0 ) and ( 1,0 )

Step-by-step explanation:

2x^2-x-1 = -1

2x^2-x = 0

x(2x-1) = 0

x=0

x=0.5 or 1/2

8 0

3 years ago

For the sequence below, identify the type of sequence and important features

Romashka-Z-Leto [24]

Hey there!

The answer would be B. Geometric sequence with an initial value of 7 and a growth factor of 2. The first, or initial value is 7 in the sequence and each number is multiplied by 2 as the sequence goes on.

Hope this helps !

7 0

3 years ago

Factor f(x)=x4-x3-7x2+13x-6 completely. Then Sketch the graph

Dennis_Churaev [7]

ANSWER TO QUESTION 1

$f(x)=(x-2)(x+3)(x-1)^2$ .

EXPLANATION

The function given to us is,

$f(x)=x^4-x^3-7x^2+13x-6$

According to rational roots theorem,

$\pm1,\pm2,\pm3,\pm6$ are possible rational zeros of

$f(x)=x^4-x^3-7x^2+13x-6$ .

We find out that,

$f(-3)=(-3)^4-(-3)^3-7(-3)^2+13(-3)-6$

$f(-3)=81+27-63-39-6$

$f(-3)=6-6$

$f(-3)=0$

Also

$f(2)=(2)^4-(2)^3-7(2)^2+13(2)-6$

$f(2)=16-8-28+26-6$

$f(2)=6-6$

$f(2)=0$

This implies that

$x-2 and x+3$ are factors of

$f(x)=x^4-x^3-7x^2+13x-6$ and hence $(x-2)(x+3)=x^2+x-6$ is also a factor.

We perform the long division as shown in the diagram.

Hence,

$f(x)=(x-2)(x+3)(x-1)^2$ .

ANSWER TO QUESTION 2

Sketching the graph

We can see from the factorization that the roots

$x=2$ and $x=-3$ have a multiplicity of 1, which is odd. This means that the graph crosses the x-axis at this intercepts.

Also the root $x=1$ has a multiplicity of 2, which is even. This means the graph does not cross the x-axis at this intercept.

Now we determine the position of the graph on the following intervals,

$x\le -3$

$f(-4)=(-4)^4-(-4)^3-7(-4)^2+13(-4)-6$

$f(-4)=150\:>0$

$-3\le x \le 1$

$f(0)=-6\:$

$1\le x\le 2$

$f(1.5)=-0.56\:$

$x \ge 2$

$f(3)=24\:>0$

We can now use these information to sketch the function as shown in diagram

4 0

3 years ago