Answer:
Step-by-step explanation:
Given that a professor sets a standard examination at the end of each semester for all sections of a course. The variance of the scores on this test is typically very close to 300.
(Two tailed test for variance )
Sample variance =480
We can use chi square test for testing of hypothesis
Test statistic = 
p value = 0.0100
Since p <0.05 our significance level, we reject H0.
The sample variance cannot be claimed as equal to 300.
ANSWER
My answer is in the photo above
I think it means grater or less ? Or positive or negative?
Answer:
B) is correct; on average, each bag of candy has a weight that is 2.6 oz different than the mean weight of 5 oz.
To find the mean absolute deviation, we first find the mean. Find the sum of the data points and divide by the number of data points (without the outlier, 21, in it):
(10+3+7+3+4+6+10+1+2+4)/10 = 50/10 = 5
Now we find the difference between each data point and the mean, take its absolute value, and find their sum:
|10-5|+|3-5|+|7-5|+|3-5|+|4-5|+|6-5|+|10-5|+|1-5|+|2-5|+|4-5| =
5+2+2+2+1+1+5+4+3+1 = 26
We now divide this by the number of data points:
26/10 = 2.6
This is a measure of how much each bag of candy varies from the mean.
Answer:(5/4,0)
Step-by-step explanation:
