Answer:
C. ± 2.326 years.
Step-by-step explanation:
We have the standard deviation for the sample. So we use the t-distribution to solve this question.
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so ![z = 2.326/tex]Now, find the width of the interval[tex]W = z*\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=z%20%3D%202.326%2Ftex%5D%3C%2Fp%3E%3Cp%3E%3Cstrong%3ENow%3C%2Fstrong%3E%2C%20find%20the%20width%20of%20the%20interval%3C%2Fp%3E%3Cp%3E%5Btex%5DW%20%3D%20z%2A%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
In which 
is the standard deviation of the population and n is the size of the sample.
In this question:
So
The correct answer is:
C. ± 2.326 years.
Answer:Yes that is correct, 3(2t + d) is equal to 6t+3d. This is due to the distributive property of multiplication, or as I like to call it, the DPM. The DPM works for all multiplication and praentheses problems. For example, 7(2t+3d)=14t+21d. You multiply the coefficient of the whole parentheses by each number/variable in the equation. Another example is 5(n+s)=5n+5s.
Answer:
y = x-4
Step-by-step explanation:
y = -x-5
Slope of line is -1.
Slope of perpendicular to line is 1.
Point-slope equation for line of slope 1 that passes through (6,2):
y-2 = 1(x-6)
Rearrange equation to slope-intercept form:
y = 1(x-6) + 2
y = x-4
First, we're going to see the candies per minute that machine C packs.
150 / 2 = 75
Now that we know that machine C packs 75 candies per minute, we're going to multiply the candies machine C makes by 11 minutes.
75 x 11 = 825
We're now gonna do the same with machine D.
130 x 11 = 1430
Then we're going to find the difference between machine C and machine D, we do this because the question basically asks how much more candies can machine D pack than machine C.
1430 - 825 = 605 candies.
This is how we find our final answer.
Our answer would be D) 605.
Hope this helps!~
Y=-5x-2
-2= y-intercept
-5x= slope
find y-intercept on a graph, make a dot.
then use slope from y-intercept dot, make another dot.
Draw line.
Is it a positive or Negative slope?
Hope that helps.
