Given:
Quadrilateral ABCD is inscribed in a circle P.
To find:
Which statement is necessarily true.
Solution:
Quadrilateral ABCD is inscribed in a circle P.
Therefore ABCD is a cyclic quadrilateral.
In cyclic quadrilateral, opposite angles form a supplementary angles.
⇒ m∠A + m∠C = 180° --------- (1)
⇒ m∠B + m∠D = 180° --------- (2)
By (1) and (2),
⇒ m∠A + m∠C = m∠B + m∠D
This statement is necessarily true for the quadrilateral ABCD in circle P.
R = 3
6x3=18
18x3=54
54x3=162 ...
Answer:
1 + 2sqrt(3)/3
Step-by-step explanation:
tan(30) = sqrt(3)/3
sin(90) = 1
tan(60) = sqrt(3)
cot(60) = 1/sqrt(3) = sqrt(3)/3
sqrt(3)/3 + 1 + sqrt(3)/3
1 + 2sqrt(3)/3
Step-by-step explanation:
Angles in a quadrilateral add to 360 degrees. So, x = 360-88-142-106=24 degrees
Answer:
The functions that represent this situation are A and C.
Step-by-step explanation:
A geometric sequence goes from one term to the next by always multiplying or dividing by the same value.
In geometric sequences, the ratio between consecutive terms is always the same. We call that ratio the common ratio.
This is the explicit formula for the geometric sequence whose first term is k and common ratio is r
