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cricket20 [7]
3 years ago
9

If the angles of a quadrilateral measure 67 degrees 123 degrees and 58 degrees what is the measure of the other angle

Mathematics
1 answer:
Cloud [144]3 years ago
7 0
The other angle measures 112°.
All the angles in any 4-sided polygon will add up to 360°, like how all angles in a triangle add up to 180°. A good way to remember this is with the sum of interior angles formula:
180 x (n - 2), where n is the number of sides.

Hope that helps! if you liked this answer please rate it as brainliest so i can gain the next rank!! thank you!!!!
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Kyle is 12 years older than Susan. Last year, he was twice as old as Susan.
iogann1982 [59]

Answer:

13 and 25

Step-by-step explanation:

um so dont hold me to this, but if he's twelve years older than susan she would've been twelve and he would've been 24 last year.

3 0
3 years ago
Find the volume of the solid generated by revolving the region bounded by
Rama09 [41]

Answer:

V =\dfrac{25\pi}{\sqrt{2}}

Step-by-step explanation:

given,

y=5√sinx

Volume of the solid by revolving

V = \int_a^b(\pi y^2)dx

a and b are the limits of the integrals

now,

V = \int_a^b(\pi (5\sqrt{sinx})^2)dx

V =25\pi \int_{\pi/4}^{\pi/2}sinxdx

\int sin x = - cos x

V =25\pi [-cos x]_{\pi/4}^{\pi/2}

V =25\pi [-cos (\pi/2)+cos(\pi/4)]

V =25\pi [0+\dfrac{1}{\sqrt{2}}]

V =\dfrac{25\pi}{\sqrt{2}}

volume of the solid generated is equal to V =\dfrac{25\pi}{\sqrt{2}}

4 0
3 years ago
The diameter of a circle is 8 inches. What is the area? 8 pi iThe diameter of a circle is 8 inches. What is the area? 8 pi inche
Aleksandr [31]

Answer:

16pi inches squared is the answer

Step-by-step explanation:

9 0
3 years ago
Read 2 more answers
Once again assistance is needed. Help!!!!
tatiyna

Answer:

D

Step-by-step explanation:

hope this helps

8 0
3 years ago
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Find the vertices of the hyperbola. Enter the smallest coordinate first.
melisa1 [442]

Answer:

([-3], [0]), ([3], [0])

Step-by-step explanation:

The given equation of the hyperbola is presented as follows;

\dfrac{x^2}{9} - \dfrac{y^2}{49} = 1

The vertices of an hyperbola (of the form)  \dfrac{x^2}{a^2} - \dfrac{y^2}{b^2} = 1 are (± a, 0)

The given hyperbola can we presented in a similar form as follows;

\dfrac{x^2}{9} - \dfrac{y^2}{49} = \dfrac{x^2}{3^2} - \dfrac{y^2}{7^2} = 1

Therefore, by comparison, the vertices of the parabola are (± 3, 0), which gives;

The vertices of the parabola are ([-3], [0]), ([3], [0]).

4 0
3 years ago
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