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Citrus2011 [14]
3 years ago
5

A collection of triangular and square tiles contain 50 pieces and 170 sides. Write and solve a system to find how many triangula

r and square tiles there are.
Mathematics
1 answer:
Lostsunrise [7]3 years ago
8 0

Answer:

30 triangular tiles and 20 square tiles

Step-by-step explanation:

hope this helps

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Which one is correct? Please hurry <3
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Answer:

a.  how many tries do u have.

Step-by-step explanation:

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HELP PLEASE !!!! Rosana used linear combination to solve the system of equations shown. She did so by multiplying the second equ
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She must have multiplied it by 5.

That would've given her:

x - y = 15
2.5x + y = 25

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(b) Find the value of 3^6​
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3 years ago
Dill and Bromberg, Problem 1.23. The San Francisco football team plays better in fair weather. They have a 70% chance of winning
shtirl [24]

Answer:

a) 40% probability that San Francisco will win.

b) 80% probability that the weather was bad

Step-by-step explanation:

We have these following probabilities:

60% chance of snow(bad weather).

If there is bad weather, 20% probability of SF winning.

100-60 = 40% chance of good weather.

If there is good weather, 70% probability of SF winning.

(a) If they play in the Super Bowl in Wisconsin and the weatherman predicts a 60% chance of snow that day, what is the probability that San Francisco will win.

20% of 60%, plus 70% of 40%. So

0.2*0.6 + 0.7*0.4 = 0.4

40% probability that San Francisco will win.

(b) Given that San Francisco lost, what is the probability that the weather was bad?

We use the conditional probability formula to solve this question.

Conditional probability:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: SF losing

Event B: Bad weather

P(A)

From a), 40% probability that SF wins. So 100-40 = 60% = 0.6 probability that SF losses.

So P(A) = 0.6

P(A and B)

60% chance of snow. If it snows, 80% probability of SF losing. So

P(A \cap B) = 0.6*0.8 = 0.48

P(B|A) = \frac{0.48}{0.60} = 0.8

80% probability that the weather was bad

6 0
3 years ago
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