Refer to the diagram shown below.
Let m = the mass (g) of the door.
Let v = the launch velocity
Let u = the velocity of the door after impact.
Elastic impact (rubber ball):
The rubber ball bounces off the door with presumably elastic impact, which means that both momentum and kinetic energy are conserved.
Conservation of momentum requires that
400v = -400v + mu
Therefore

Inelastic impact (clay):
The clay sticks to the door after impact.
Conservation of momentum requires that
400g = (m+400)u
Therefore

When we compare magnitudes of u for the door, we find that

Clearly, the elastic impact creates a greater value of u for the door.
Answer:
The rubber ball creates a larger impulse to the door because the nature of its impact is approximately elastic.
Here, you need to apply second equation of Kinematics
S = ut + 1/2 at²
s = at²/2 [ As initial velocity (u) = 0 ]
Now, a = 9.8 m/s²
t = 2.7 s
Substitute their values in the formula:
s = 9.8 × (2.7)² / 2
s = 35.721 m
After rounding-off to the nearest hundredth value, it would be 36 m
Finally, your answer would be option B.
Hope this helps!
Answer:
Black holes do not have a bottom.
Explanation:
Hope this helps :)
Answer:
No.
Explanation:
The only way a twist may be done is if the trans form of an alkene/alkyne is twisted into the cis form--only if/when the pi bond is brokwn.