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Sloan [31]
3 years ago
8

In carbon dioxide (CO2), there are two oxygen atoms for each carbon atom. Each oxygen atom forms a double bond with carbon, so t

he molecule contains two sets of double bonds. Two sets of double bonds means that the total number of electrons being shared in the molecule is (a) 2. (b) four. (c) 6. (d) 8
Physics
1 answer:
Anton [14]3 years ago
5 0

ANSWER: d) 8

EXPLANATION: Two sets of two shared electrons (4 electrons total shared) = one set of a double covalent bond.

Therefore, 8 electrons total shared = two sets of double covalent bonds

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In a car lift used in a service station, compressed air exerts a force on a small piston that has a circular cross section and a
timofeeve [1]

Answer:

a) F₁ = 1.48 x 10³ N

b) P = 1.88*10⁵ Pa

c) The work  is equal in both pistons

Explanation:

Pascal´s Principle can be applied in the hydraulic press:

If we apply a small force (F₁) on a small area piston (A₁), then, a pressure (P) is generated that is transmitted equally to all the particles of the liquid until it reaches a larger area piston and therefore a force (F₂) can be exerted that is proportional to the area(A₂) of the piston.

Pressure is defined as the force per unit area:

P=\frac{F}{A}  Formula (1)

P₁=P₂

\frac{F_{1} }{A_{1} } =\frac{F_{2} }{A_{2} } Formula (2)

Data

r₁= 5 cm = 0.05 m

r₂= 15 cm = 0.15 m

F₂=  13300N

Area of the pistons (A₁,A₂)

A=π*r² : Area of the circle

A₁ = π*(0.05)²=7.85*10⁻³ m²

A₂= π*(0.15)²= 70.69*10⁻³ m²

a) Force that compressed air must exert to lift a car weighing 13300 N

We replace data in the formula (2)

\frac{F_{1} }{A_{1} } =\frac{F_{2} }{A_{2} }

F_{1} = \frac{13300*7.85*10^{-3} }{70.69*10^{-3} }

F₁ =  1.48 x 10³ N

b) Air pressure produced by F₁

We replace data in the formula (1)

P=\frac{F}{A}

F₁ =  1.48 x 10³ N , A₁ = 7.85*10⁻³ m²

P=\frac{1.48*10^{3} }{7.85*10^{-3} }

P= 1.88*10⁵ Pa

c)The volume of liquid displaced by the small piston is distributed in a thin layer on the large piston, so that the product of the force by the displacement (the work) is equal in both pistons.

3 0
3 years ago
What kind of friction exists between solid objects moving in water?
Stels [109]
The best and most correct answer among the choices provided by the question is  drag<span>.

</span><span>Drag </span>kind of friction exists between solid objects moving in water.

Hope my answer would be a great help for you.    
If you have more questions feel free to ask here at Brainly.  
6 0
3 years ago
If the net force acting on a stationary object is zero then the object will
Drupady [299]
If the net force is zero, then there is no acceleration, which means no change in velocity. The velocity starts at zero, so it must remain at zero. Therefore, the object will not move.
7 0
3 years ago
A 1.65 mol sample of an ideal gas for which Cv,m = 3R/2 undergoes the following two-step process:1) from an initial state of the
kirill [66]

Answer:

W = -1.97KJ, Q = 1.97KJ, Delta U = 0

Delta U = -1.03KJ, Q = -1.03KJ, Delta H = -1.72KJ

Explanation:

The deatiled step by step calculation using the ideal gas equation (Pv =nRT), The first law of thermodynamics ( dQ =dW + dU) as applied is as shown in the attached file.

7 0
3 years ago
Two loops of wire are arranged so that a changing current in one will induce a current in the other. If the current in the first
patriot [66]

Answer:

The current in the second loop will stay constant

Explanation:

Since the induced emf in the second coil, ε due to the changing current i₁ in the first wire loop ε = -Mdi₁/dt where M = mutual inductance of the coils and di₁/dt = rate of change of current in the first coil = + 1 A/s (positive since it is clockwise)

Now ε = i₂R where i₂ = current in second wire loop and R = resistance of second wire loop.

So,  i₂R = -Mdi₁/dt

i₂ = -Mdi₁/dt/R

Since di₁/dt = + 1 A/s,

i₂ = -Mdi₁/dt/R

i₂ = -M × + 1 A/s/R

i₂ = -M/R

Since M and R are constant, this implies that i₂ = constant

<u>So, the current in the second wire loop will stay constant.</u>

3 0
3 years ago
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