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Sloan [31]
3 years ago
8

In carbon dioxide (CO2), there are two oxygen atoms for each carbon atom. Each oxygen atom forms a double bond with carbon, so t

he molecule contains two sets of double bonds. Two sets of double bonds means that the total number of electrons being shared in the molecule is (a) 2. (b) four. (c) 6. (d) 8
Physics
1 answer:
Anton [14]3 years ago
5 0

ANSWER: d) 8

EXPLANATION: Two sets of two shared electrons (4 electrons total shared) = one set of a double covalent bond.

Therefore, 8 electrons total shared = two sets of double covalent bonds

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An increase of 50 dB increases the sound intensity by a factor of
Artemon [7]

A factor of 50dB = a factor of 10^(50/10) = 10^5 = a factor of <em>100,000</em> .


5 0
4 years ago
A car goes from rest to a velocity of 108 km/h north in 10s what is the car's acceleration in m/s2
fomenos

initial velocity of the car given as

v_i = 0

final velocity is given as

v_f = 108 km/h

as we know that

1 km/h = 0.277 m/s

now we can convert final speed into m/s

v_f = 108 * 0.277 = 30 m/s

now acceleration is rate of change in velocity

a = \frac{v_f - v_i}{t}

a = \frac{30 - 0}{10}

a = 3 m/s^2

so the acceleration of the car is 3 m/s^2

7 0
3 years ago
During an investigation, a student determines that a copper sample has a density of 8.10 g/ml. What is the students percent erro
Roman55 [17]
<span>During an investigation, a student determines that a copper sample has a density of 8.10 g/ml. What is the students percent error of the accepted density for copper is 8.96 g/ml </span>

5 0
4 years ago
When you and a friend move a couch to another room, you exert a force of 75 N over 5 m. How much work did you do?
bagirrra123 [75]

Answer:375J

Explanation:

Force=75N

Distance=5m

Work=force x distance

Work=75 x 5

Work=375J

5 0
3 years ago
A cliff jumper jumps off a cliff with an initial horizontal velocity of 10 m/s. The cliff is 10 meters high. How far from the ba
nalin [4]

Answer:

The distance reached is 14.3 m.

Explanation:

To find the distance reached by the diamond first we need to find the flight time:

t_{v} = \sqrt{\frac{2h}{g}}

Where:

h: is the height = 10m

g: si the gravity = 9.81 m/s²

t_{v} = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2*10 m}{9.81 m/s^{2}}} = 1.43 s

Now, we can find the distance reached:

x = V_{0_{x}}*t_{v}

Where:

V_{0_{x}} is the initial horizontal velocity = 10 m/s

x = V_{0_{x}}*t_{v} = 10 m/s*1.43 s = 14.3 m

Therefore, the distance reached is 14.3 m.

I hope it helps you!    

3 0
3 years ago
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