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Sloan [31]
3 years ago
8

In carbon dioxide (CO2), there are two oxygen atoms for each carbon atom. Each oxygen atom forms a double bond with carbon, so t

he molecule contains two sets of double bonds. Two sets of double bonds means that the total number of electrons being shared in the molecule is (a) 2. (b) four. (c) 6. (d) 8
Physics
1 answer:
Anton [14]3 years ago
5 0

ANSWER: d) 8

EXPLANATION: Two sets of two shared electrons (4 electrons total shared) = one set of a double covalent bond.

Therefore, 8 electrons total shared = two sets of double covalent bonds

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An electrically neutral atom has the same # of protons and electrons true or false ?
Airida [17]

Answer:

True

Explanation:

A neutral atom has same no. of protons and electron that's why they are neutral.

5 0
3 years ago
Read 2 more answers
Plz answer my question below....
katrin2010 [14]
It should be YY or Yg
7 0
3 years ago
Half life of a given sample of radium is 22 years the sample will reduce to 25% of its original value after
makkiz [27]

Answer:

44 years

Explanation:

Use half life equation:

A = A₀ (½)^(t / T)

where A is the final amount,

A₀ is the initial amount,

t is time,

and T is the half life.

0.25 A₀ = A₀ (½)^(t / 22)

0.25 = (½)^(t / 22)

t / 22 = 2

t = 44

3 0
3 years ago
What is the energy of light that must be absorbed by a hydrogen atom to transition an electron from n = 3 to n = 5?
alina1380 [7]

Answer:

The energy absorbed by a hydrogen atom is 1.549 X10⁻¹⁹ J

Explanation:

Using Bohr's equation; the energy absorbed by the hydrogen atom can be calculated as follows:

\delta E = (\frac{1}{n_2{^2}} -\frac{1}{n_1^{2}})13.6eV

When an electron moves from a lower energy level to a higher energy level, energy is absorbed by the atom.

Lower energy level (n₂) = 3

Higher energy level (n₁) = 5

1 eV = 1.602X10⁻¹⁹ C

\delta E = (\frac{1}{3{^2}} -\frac{1}{5^{2}})13.6X1.602X10^{-19}

ΔE = 1.549 X10⁻¹⁹J

The energy absorbed by a hydrogen atom  to transition an electron from n = 3 to n = 5 is 1.549 X10⁻¹⁹ J

4 0
3 years ago
A roller coaster has a mass of 450 kgIt sits at the top of a hill with height 49 m. If it drops from this hill, how fast is it g
fgiga [73]

The speed of the roller coater at the bottom of the hill is 31 m/s.

<h3>Speed of the roller coater at the bottom of the hill</h3>

Apply the principle of conservation of mechanical energy as follows;

K.E(bottom) = P.E(top)

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

  • v is the speed of the coater at bottom hill
  • h is the height of the hill
  • g is acceleration due to gravity

v = √(2 x 9.8 x 49)

v = 31 m/s

Thus, the speed of the roller coater at the bottom of the hill is 31 m/s.

Learn more about speed here: brainly.com/question/6504879

#SPJ1

6 0
2 years ago
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