9514 1404 393
Answer:
B
Step-by-step explanation:
The given equation is in slope-intercept form:
y = mx + b
where the slope is m = -3 and the y-intercept is b = +2.
So, the graph will have a slope of ...
"rise"/"run" = -3 = -3/1
and will cross the y-axis at y=2.
Graphs A and B cross the y-axis in the right place, but only Graph B has a negative "rise" a x increases.
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Usually I just use slope calculator hope that helps
Formula is y = a(x-h)^2 + k
Where h is 1 and k is 1
f (x) = a(x-1)^2 + 1
-3 = a(0-1)^2 + 1
-3 = a(-1)^2 + 1
-3 = a(1) + 1
-3 - 1 = a
-4 = a
a = -4
A must be equal to -4
y = -4(x-1)^2 + 1
0 = -4(x-1)^2 + 1
4(x^2 - 2x + 1) - 1 = 0
4x^2 - 8x + 4 - 1 = 0
4x^2 - 8x + 3 = 0
4x^2 - 8x = -3
Divide fpr 4 each term of the equation....x^2 - 2x = -3/4
We must factor the perfect square ax^2 + bx + c which we don't have. We must follow the rule (b/2)^2 where b is -2....(-2/2)^2 =
(-1)^2 = 1 and we add up that to both sides
x^2 - 2x + 1 = -3/4 + 1
x^2 - 2x + 1 = 1/4
(x-1)^2 = 1/4
square root both sides x-1 = (+/-) 1/2
x1 = +1/2 + 1 = 3/2
x2 = -1/2 + 1 = 1/2
x-intercepts are 1/2 and 3/2, in form (3/2,0); (1/2,0)
- 3 + 3x = 2x – 13
Bring -3 to the right side of the equation by adding 3 to both sides
(- 3 + 3) + 3x = 2x – 13 + 3
0 + 3x = 2x - 10
3x = 2x - 10
Bring 2x to the other side by subtracting 2x to both sides
3x - 2x = 2x - 2x - 10
x = -10
Check:
-3 + 3(-10) = 2(-10) - 13
-3 + (-30) = -20 - 13
-33 = -33
Hope this helped!
~Just a girl in love with Shawn Mendes
