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3 years ago

I tried.....but it’s confusing

Mathematics

2 answers:

bixtya [17]3 years ago

5 0

Answer:

just add it all up with the percent of the coin

Step-by-step explanation:

Svetllana [295]3 years ago

3 0

Answer:

$1025

Step-by-step explanation:

31 x 10= 310

14 x 5= 210

4 x 2= 8

62 x 1= 1

and that was the bills, add them together, you get 529.

then multiply the amount of what the change is by the amount of change there is so, 13 x 25= 325 3 x 5= 15 and 93 x 1= 93.

add the change

325+15+93= 433

add the amount of how much each totals were worth:

433+592 = $1025

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write tge equation for the following scenario. Then model and solve. Maria bought 5 jackets online.she paid $10 for shipping. if

Marizza181 [45]

If 5 jackets where bought and Maria paid $10 for shipping then each jacket would equal 12 because 12x5= 60+10= $70

3 0

3 years ago

18.79+2.11+(-1.92)+17.28

stellarik [79]

Answer:

36.26

Step-by-step explanation:

Hope this helps. Plz give brainliest.

7 0

3 years ago

Help much needed here

Reil [10]

Hello : let A(-1,5) B(5,-4)<span>
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8 0

3 years ago

Soap films and bubbles are colorful because the interference conditions depend on the angle of illumination (which we aren't cov

mylen [45]

Answer:

56.39 nm

Step-by-step explanation:

In order to have constructive interference total optical path difference should be an integral number of wavelengths (crest and crest should be interfered). Therefore the constructive interference condition for soap film can be written as,

$2t=(m+\frac{1}{2} ).\frac{\lambda}{n}$

where λ is the wavelength of light and n is the refractive index of soap film, t is the thickness of the film, and m=0,1,2 ...

Please note that here we include an additional 1/2λ phase shift due to reflection from air-soap interface, because refractive index of latter is higher.

In order to have its longest constructive reflection at the red end (700 nm)

$t_1=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_1=\frac{1}{2} .\frac{700}{(2)*(1.33)}\\ \\ t_1=131.58\ nm$

Here we take m=0.

Similarly for the constructive reflection at the blue end (400 nm)

$t_2=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_2=\frac{1}{2} .\frac{400}{(2)*(1.33)}\\ \\ t_2=75.19\ nm$

Hence the thickness difference should be

$t_1-t_2=131.58-75.19=56.39 \ nm$

7 0

3 years ago

a city has a population of 340,000 people suppose each year the population grows by 7% what will rhe population be after 12 year

NemiM [27]

So this is going to be an exponential equation, which the format is $y=ab^x$ , in which a is the initial value and b is the growth/decay rate.

In this case, a is going to be 340,000 and b is going to be 107%, or 1.07, since the population is going to be increasing by 7% and the equation is now $y=340000(1.07)^x$ .

Now replace x with 12 and solve.

$y=340000(1.07)^{12}$

Solve $1.07^{12}$ , and then if you don't round that answer and multiply it with 340000 you get $y=765745$ .

6 0

3 years ago