I've already answered the question. So it is::
A is c and a because it's on the left of 0.
B is b and d because it's on the right of 0.
C is additive inverse.
There are 36 different possibilities for his lunch.
We can use the fundamental counting principal to solve this problem. We simply need to find the number of options for each part of the meal and multiply them.
Sandwich = 3
Snack = 3
Dessert = 2
Drink = 2
3 x 3 x 2 x 2 = 36
Answer:
8x4x2=64+24=88 the answer is 88 yw :) pls give brainliest
Step-by-step explanation:
144 I believe
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veronica howard