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3 years ago

8

P=(2s + 4)+ (3s + 1)

1 answer:

skad [1K]3 years ago

3 0

Since there is an addition symbol in the middle all you need to do is combine like terms/add. Your final answer should be:
p= 5s+5

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What are the solutions to the quadratic equation 5x2 + 60x = 0?

const2013 [10]

5x^2+60x=0
x(5x+60)=0

x=0
and
5x+60=0
5x=-60
x=-12

therefore, the first option is correct

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4 years ago

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Sonia is planning a rectangular vegetable garden using a roll of border fencing that is 45 3/4 feet long. If she makes the width

Verizon [17]

Answer: 12 3/8 10 1/2 + 10 1/2= 21 45 3/4 - 21 = 24 3/4 24 ÷ 2 = 12 Change the 3/4 into 8ths = 6/8 Divide that in half which gives you 3/8 So the length is 12 3/8

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3 years ago

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In the right triangle above a=2.7 and b=4.3. Find the value of c, rounded to the nearest tenth

morpeh [17]

Answer:

5.1

Step-by-step explanation:

Since there is no diagram provided here, we assume that c is the length of the hypotenuse, so we have ...

c² = a² +b² . . . . . . Pythagorean theorem

c² = 2.7² +4.3² = 25.78

c = √25.78 ≈ 5.0774

c ≈ 5.1

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4 years ago

Match each series with the equivalent series written in sigma notation

PIT_PIT [208]

Answer:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

$3 + 12 + 48 + 192 + 768$

The expression can be written as:

$3 \to 3*4^{0$ --- 0

$12 \to 3 * 4^{1$ ---- 1

$48 \to 3 * 4^{2$ --- 2

$192 \to 3 * 4^{3$ ---- 3

$768 \to 3 * 4^{4$ ---- 4

For the nth term, the expression is:

$Term = 3 * 4^{n$ ---- n

So, the summation is:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

Solving (b):

$4 + 32 + 256 + 2048 + 16384$

The expression can be written as:

$4 \to 4 * 8^0$ --- 0

$32 \to 4 * 8^1$ ---- 1

$256 \to 4 * 8^2$ --- 2

$2048 \to 4 * 8^3$ ---- 3

$16384 \to 4 * 8^4$ ---- 4

For the nth term, the expression is:

$Term \to 4 * 8^n$ ---- n

So, the summation is:

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

Solving (c):

$2 + 6 + 18 + 54 + 162$

The expression can be written as:

$2 \to 2 * 3^0$ --- 0

$6 \to 2 * 3^1$ ---- 1

$18 \to 2 * 3^2$ --- 2

$54 \to 2 * 3^3$ ---- 3

$162 \to 2 * 3^4$ ---- 4

For the nth term, the expression is:

$Term \to 2 * 3^n$ ---- n

So, the summation is:

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

Solving (d):

$3 + 15 + 75 + 375 + 1875$

The expression can be written as:

$3 \to 3 * 5^0$ --- 0

$15 \to 3 * 5^1$ ---- 1

$75 \to 3 * 5^2$ --- 2

$375 \to 3 * 5^3$ ---- 3

$1875 \to 3 * 5^4$ ---- 4

For the nth term, the expression is:

$Term \to 3 * 5^n$ ---- n

So, the summation is:

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

5 0

3 years ago

The local Beep Boop store sells widgets and gizmos. If you subtract the cost of 3 gizmos from 7 widgets you would spend 28 Boop

jasenka [17]

Answer:

$7

Step-by-step explanation:

8 0

3 years ago