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Dmitriy789 [7]
3 years ago
5

During one season a football team had 15 wins this was 60% of the total games they played. how many games did they play?

Mathematics
1 answer:
xeze [42]3 years ago
6 0

Answer: They played 25 games

Step-by-step explanation: If they had 15 wins and the total games they played is 60% then they lost 10 times and they played 25 games because if you divide 15 by 60 you get 0.25 so they played 25 games.

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what is the approximate distance from one corner of the soccer field to the opposite corner 60 yards, 100 yards
aalyn [17]

Answer:

Using Pythagorean theorem:

Diagonal = sqrt( 60^2 + 100^2) = 116.62

Hope this helps!

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7 0
3 years ago
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natali 33 [55]

Answer:

B. f (4) = 4 · 20^{3}

Step-by-step explanation:

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6 0
3 years ago
Please help? Graph <img src="https://tex.z-dn.net/?f=-3x%5E2%2B12y%5E2%3D84" id="TexFormula1" title="-3x^2+12y^2=84" alt="-3x^2+
mariarad [96]
-3x^2+12y^2=84
12y^2=3x^2+84
y^2=\dfrac{x^2}4+7
y=\pm\sqrt{\dfrac{x^2}4+7}

For either square root to exist, you require that \dfrac{x^2}4+7\ge0. This is true for all x, since \dfrac{x^2}4 is always non-negative. This means the domain of y as a function of x is all real numbers, or x\in\mathbb R or (-\infty,infty).

Now, because \dfrac{x^2}4+7 is non-negative, and the smallest value it can take on is 7, it follows that the minimum value for the positive square root must be \sqrt7, while the maximum value of the negative root must be -\sqrt7. This means the range is y\in\mathbb R\setminus(-\sqrt7,\sqrt7), or |y|\ge\sqrt7, or (-\infty,-\sqrt7]\cup[\sqrt7,\infty).
6 0
4 years ago
One way of solving systems of linear equations is by adding a multiple of one equation to the other. the multiplier for one equa
elena-s [515]
We want to use elimination to solve
y = 0                     (1)
x + y = 40             (2)

Multiply (1) by -1 to eliminate y.
-y = 0                    (3)

Add (2) and (3).
x + y + (-y) = 40 + 0
x = 40

Answer: Multiply by -1.
3 0
3 years ago
Solve: 3 + 5n = 5(n + 2) - 7 * what solution is it and please explain i need a good grade
mrs_skeptik [129]

Answer:

3+5n=5(n+2)-7*

We move all terms to the left:

3+5n-(5(n+2)-7*)=0

We calculate terms in parentheses: -(5(n+2)-7*), so:

5(n+2)-7*

We add all the numbers together, and all the variables

5(n+2)

We multiply parentheses

5n+10

Back to the equation:

-(5n+10)

We get rid of parentheses

5n-5n-10+3=0

We add all the numbers together, and all the variables

-7!=0

There is no solution for this equation

   

Step-by-step explanation:

6 0
3 years ago
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