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erik [133]
3 years ago
14

One way of solving systems of linear equations is by adding a multiple of one equation to the other. the multiplier for one equa

tion is chosen so that one of the two variables will cancel out in the sum. what should you multiply the equation y=0 by so that when added to x+y=40 the variable y will cancel out?
Mathematics
1 answer:
elena-s [515]3 years ago
3 0
We want to use elimination to solve
y = 0                     (1)
x + y = 40             (2)

Multiply (1) by -1 to eliminate y.
-y = 0                    (3)

Add (2) and (3).
x + y + (-y) = 40 + 0
x = 40

Answer: Multiply by -1.
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DiKsa [7]
Just plug in 4 for the x

2*4 +4y =36
8+4y =36
4y =36-8
4y=28
y= 28/4
y=7
7 0
2 years ago
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g An urn contains 150 white balls and 50 black balls. Four balls are drawn at random one at a time. Determine the probability th
xxTIMURxx [149]

Answer:

With replacement, 0.2109 = 21.09% probability that there are 2 black balls and 2 white balls in the sample.

Without replacement, 0.2116 = 21.16% probability that there are 2 black balls and 2 white balls in the sample.

Step-by-step explanation:

For sampling with replacement, we use the binomial distribution. Without replacement, we use the hypergeometric distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Sampling with replacement:

I consider a success choosing a black ball, so p = \frac{50}{150+50} = \frac{50}{200} = 0.25

We want 2 black balls and 2 white, 2 + 2 = 4, so n = 4, and we want P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{4,2}.(0.25)^{2}.(0.75)^{2} = 0.2109

With replacement, 0.2109 = 21.09% probability that there are 2 black balls and 2 white balls in the sample.

Sampling without replacement:

150 + 50 = 200 total balls, so N = 200

Sample of 4, so n = 4

50 are black, so k = 50

We want P(X = 2).

P(X = 2) = h(2,200,4,50) = \frac{C_{50,2}*C_{150,2}}{C_{200,4}} = 0.2116

Without replacement, 0.2116 = 21.16% probability that there are 2 black balls and 2 white balls in the sample.

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What number is the same percent of 36 as 5 is of 24?<br> If possible please show work:))
kiruha [24]

Answer:

7.4999999988

Step-by-step explanation:

5/24=0.2083333333

5 is 20.8% of 24

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Sloan [31]

Answer:

<h3>#1</h3>

<u>Rectangle area:</u>

  • A = lw

<u>Given:</u>

  • l = 12 ft, A = 300 ft²

<u>Find w:</u>

  • 12w = 300
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<h3>#2</h3>

<u>Perimeter is the sum of side lengths:</u>

P = 2 1/4 + 5 2/5 + 5 17/20 =

     2 + 5 + 5 + 1/4 + 2/5 + 17/20 =

     12 + 5/20 + 8/20 + 17/20 =

     12 + 30/20 =

     12 + 1.5 =

     13.5 ft

<h3>#3</h3>
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<u>Total cost:</u>

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Answer:

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Step-by-step explanation:

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