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erik [133]
3 years ago
14

One way of solving systems of linear equations is by adding a multiple of one equation to the other. the multiplier for one equa

tion is chosen so that one of the two variables will cancel out in the sum. what should you multiply the equation y=0 by so that when added to x+y=40 the variable y will cancel out?
Mathematics
1 answer:
elena-s [515]3 years ago
3 0
We want to use elimination to solve
y = 0                     (1)
x + y = 40             (2)

Multiply (1) by -1 to eliminate y.
-y = 0                    (3)

Add (2) and (3).
x + y + (-y) = 40 + 0
x = 40

Answer: Multiply by -1.
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Answer:

The step 4 and 5 describe the errors Stephen made.

Step-by-step explanation:

Given : Stephen evaluated (6.34\times 10^{-7})(4.5\times 10^3).  His work is shown below.

To find : Which two statements describe the errors Stephen made?

Solution :

Step 1 - (6.34\times 10^{-7})(4.5\times 10^3)

Step 2 - (6.34\times 4.5)(10^{-7}\times 10^3)

Step 3 - (28.53)(10^{-4})

Step 4 - 28.53\times 10^{4}

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So correct step is 28.53\times 10^{-4}

Step 5 - 28.53\times 10^{3}

Error is the step as there is 4 in place of 3.

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The step 4 and 5 describe the errors Stephen made.

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I hope that helps! =)

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