Considering that the grows at a constant rate we can form an equation where x = how many years after it was planted
and y = its height
Now we just need to find how many feet it grows each year. To do that we just need to compare its height from a certain age to another:
6 years after it was planted : 7 feet,
so x=6 and y = 7
9 years after it was planted: 16 feet
so x= 9 y=16
With thay we can conclude that in 3 years , the tree grew 9 feet. To discover how much the tree grow each year we just nee to divide 9 feet by 3 years which is 3 feet every year.
To write the equatopn now we just need to find the y-intercept which we can discover by setting x to 0:
If in 6 years after the tree was planted it is 7 feet long , we can discover how long it was when it was planted by subtracting 6 years of growth (The slope ) which is 3
7 - 6(years)×3(feet the tree grow each year)
7 - 18 = -11
The tree was -11 feet long when it was planted
which is our y-intercept
( I know it doesnt make sense , but if you apply to a graph it will make more sense )
Now we can make the equation
y = 3x -11
Only 2 forces are out of balance - the 22N and the 14N
So the resultant force is 22-14 = 8N.
Answer:
incorrect is They have a sum of -14
Answer:
320 yards
Step-by-step explanation:
Alright, there was a lot of addition, and you're just gonna have to trust me, the answer is 320 yards
Answer:
See explanation
Step-by-step explanation:
Jane is given a $100 gift to start and saves $35 a month from her allowance.
- After 1 month, Jane has saved
- After 2 months, Jane has saved
- After three months, Jane has saved
- and so on
In general, after x months Jane has saved
This means that it makes sense to represent the relationship between the amount saved and the number of months with one constant rate (in this case the constant rate is 35). It makes sense because the amount of money increases by $35 each month. Since the amount of increase is constant, we get constant rate. Also the initial amount is known ($100), so there is a possibility to write the equation of linear function representing this situation.
