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AlladinOne [14]
2 years ago
13

Gina earns an hourly rate of $8.94 for a 40-hour week. She receives

Mathematics
1 answer:
Zarrin [17]2 years ago
8 0

Answer: $536.40

Step-by-step explanation:

8.94 * 2 = 17.88

8.94(40) + 17.88(10)

357.60 + 178.80 = $536.40

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The diameter of a circle is 1.4 centimeters. Find its area. Use 3.14 Round to the nearest
NeTakaya

Answer:

Area = 1.54

Step-by-step explanation:

Area = πr^{2}

π = 3.14

diameter = 1.4

radius (half of diameter) = 0.7

Area = 3.14 x 0.7^{2}

Area = 3.14 x 0.49

Area = 1.5386

round to the nearest hundredth:

1.5386 = 1.54

8 0
2 years ago
Read 2 more answers
I don’t understand the polynomials
Serhud [2]
Polynomial comes from poly- (meaning "many") and -nomial (in this case meaning "term") ... so it says "many terms"

A polynomial can have:

constants (like 3, −20, or ½)
variables (like x and y)
exponents (like the 2 in y2), but only 0, 1, 2, 3, ... etc are allowed
that can be combined using addition, subtraction, multiplication and division ...

... except ...

... not division by a variable (so something like 2/x is right out)

So:

A polynomial can have constants, variables and exponents,
but never division by a variable.

Also they can have one or more terms, but not an infinite number of terms.

These are polynomials:

3x
x − 2
−6y2 − ( 79 )x
3xyz + 3xy2z − 0.1xz − 200y + 0.5
512v5 + 99w5
5
(Yes, "5" is a polynomial, one term is allowed, and it can be just a constant!)



These are not polynomials

3xy-2 is not, because the exponent is "-2" (exponents can only be 0,1,2,...)
2/(x+2) is not, because dividing by a variable is not allowed
1/x is not either
√x is not, because the exponent is "½" (see fractional exponents)


But these are allowed:

x/2 is allowed, because you can divide by a constant
also 3x/8 for the same reason
√2 is allowed, because it is a constant (= 1.4142...etc)
7 0
3 years ago
I NEEDZ HELPZZZZZZZZ!!!!<br><br><br>btw i didnt mean to click d)20..
joja [24]
The slope is 0 or answer B.)
8 0
3 years ago
Part B: Give an example of an undefined term and how it relates to a circle. (5 points)
ivann1987 [24]

Answer:

hello

Step-by-step explanation:

hello

5 0
3 years ago
Read 2 more answers
Find the local max and min values of f(x)=x^2/x-1 using both first and second derivative tests
uranmaximum [27]
Hmm, the 2nd derivitve is good for finding concavity

let's find the max and min points
that is where the first derivitive is equal to 0
remember the difference quotient

so
f'(x)=(x^2-2x)/(x^2-2x+1)
find where it equals 0
set numerator equal to 0
0=x^2-2x
0=x(x-2)
0=x
0=x-2
2=x

so at 0 and 2 are the min and max
find if the signs go from negative to positive (min) or from positive to negative (max) at those points

f'(-1)>0
f'(1.5)<0
f'(3)>0

so at x=0, the sign go from positive to negative (local maximum)
at x=2, the sign go from negative to positive (local minimum)


we can take the 2nd derivitive to see the inflection points
f''(x)=2/((x-1)^3)
where does it equal 0?
it doesn't
so no inflection point
but, we can test it at x=0 and x=2
at x=0, we get f''(0)<0 so it is concave down. that means that x=0 being a max makes sense
at x=2, we get f''(2)>0 so it is concave up. that means that x=2 being a max make sense




local max is at x=0 (the point (0,0))
local min is at x=2 (the point (2,4))
6 0
3 years ago
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