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2 years ago

15

Find the area of each figure. Round your answers to the nearest hundredth 11-12

1 answer:

den301095 [7]2 years ago

4 0

Answer:

17 and 18

Step-by-step explanation:

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7x+4y-6z=-73<br> 8x+5y+6z=-59<br> -4x-8y-3z=46<br> y=

Oksanka [162]

Is this all one equation??

5 0

3 years ago

Dwayne walks a total of 960 feet around 3 sides of a square city block. Which

Ugo [173]

Answer:

The perimeter is 1280ft

Step-by-step explanation:

Let the side length of the square be s.

Then the distance around three sides is 3s.

According to the question the distance around 3 sides of a square city block is 960 feet.

This implies that:

$3s = 960$

$s = \frac{960}{3}$

$s = 320$

The perimeter of a square is

$p = 4s$

Substitute s=320 to get:

$p = 4(320)$

$p = 1280$

The perimeter is 1280 ft

5 0

3 years ago

Read 2 more answers

The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.

andrezito [222]

Answer:

Given the equation: $3x^2+10x+c =0$

A quadratic equation is in the form: $ax^2+bx+c = 0$ where a, b ,c are the coefficient and a≠0 then the solution is given by :

$x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$ ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

$x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}$

Simplify:

$x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}$

Also, it is given that the difference of two roots of the given equation is $4\frac{2}{3} = \frac{14}{3}$

i.e,

$x_1 -x_2 = \frac{14}{3}$

Here,

$x_1 = \frac{-10 + \sqrt{100- 12c}}{6}$ , ......[2]

$x_2= \frac{-10 - \sqrt{100- 12c}}{6}$ .....[3]

then;

$\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}$

simplify:

$\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}$

or

$\sqrt{100- 12c} = 14$

Squaring both sides we get;

$100-12c = 196$

Subtract 100 from both sides, we get

$100-12c -100= 196-100$

Simplify:

-12c = -96

Divide both sides by -12 we get;

c = 8

Substitute the value of c in equation [2] and [3]; to solve $x_1 , x_2$

$x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}$

or

$x_1 = \frac{-10 + \sqrt{100- 96}}{6}$ or

$x_1 = \frac{-10 + \sqrt{4}}{6}$

Simplify:

$x_1 = \frac{-4}{3}$

Now, to solve for $x_2$ ;

$x_2 = \frac{-10 - \sqrt{100- 12\cdot 8}}{6}$

or

$x_2 = \frac{-10 - \sqrt{100- 96}}{6}$ or

$x_2 = \frac{-10 - \sqrt{4}}{6}$

Simplify:

$x_2 = -2$

therefore, the solution for the given equation is: $-\frac{4}{3}$ and -2.

3 0

3 years ago

Select the correct answer.

AleksAgata [21]

The answer is d: 16y^6/x^2

3 0

2 years ago

-14x>-3 solve for x

wariber [46]

x=3/14

3 over 14

hope this helps

3 0

3 years ago