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3 years ago

What is the height h of the garage roof?

Mathematics

2 answers:

Alchen [17]3 years ago

7 0

Answer: 8 feet

Explanation:
Use Pythagorean theorem which is a^2 + b^2=c^2
30/2=15
15^2+b^2=17^2
225 +b^2= 289
289-225=64; b^2=64
8^2=64
b=missing side=8
h=8

bixtya [17]3 years ago

3 0

Answer:

8 feet

Step-by-step explanation:

because the length is 17 ft and that makes the height 8 feet high

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If y=-16 when x=4, find x when y=20.<br><br> x = ?

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Answer:

X would be equal to 5.

Step-by-step explanation:

20 divided by 16 equals 1.25.

1.25 times 4 equals to 5.

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What is the difference in area covered by a single 3 inch windshield wiper operating with a central angle of 138 degrees compare

Elena-2011 [213]

Answer:

38.9 square inches.

Step-by-step explanation:

We are asked to find the difference in area covered by a single 3 inch windshield wiper operating with a central angle of 138 degrees compared to a pair of 5 inch wipers operating together each having a central angle of 114 degrees.

We will use area of sector formula to solve our given problem as:

$\text{Area of sector}=\frac{\theta}{360}\times \pi r^2$ , where, r represents radius and theta represents central angle.

Let us find area of sector with central angle 140 degree and radius 3 inch.

$\text{Area of sector}=\frac{138}{360}\times \pi (3)^2$

$\text{Area of sector}=\frac{138}{360}\times 9\pi$

$\text{Area of sector}=10.83849$

Now, we will find area of sector with central angle 114 degree and radius 5 inch and multiply by 2 as:

$\text{Area of sector}=2(\frac{114}{360}\times \pi (5)^2)$

$\text{Area of sector}=2(\frac{114}{360}\times 25\pi)$

$\text{Area of sector}=\frac{114}{360}\times 50\pi$

$\text{Area of sector}=49.74188$

Let us find difference of area as shown below:

$\text{Difference of areas}=49.74188-10.83849$

$\text{Difference of areas}=38.90339$

$\text{Difference of areas}\approx 38.9$

Therefore, the difference in area covered is approximately 38.9 square inches.

8 0

3 years ago

I need help this plzz

guapka [62]

#1 second line: x-y=-3
x=y-3(isolating x to prepare for substitution)(what x is equivalent to)
get back to the first line
x+y=5
(y-3)+y=5(substituting the value of x of the first line with the value of x at the second line)(It is a process to find the intersection between the two lines(line#1 and line#2 are two linear functions)
2y-3=5(simplify)
2y=8(simplify)
y=4(simplify)
line#1 x+y=5
x+(4)=5(plug the value of y back into either line#1 or line#2 will work)(plugging in the y value of the point of intersection to solve for the x value of the point of intersection)
x=1(solve)
the two linear lines intersect at the point(1(x coordinate), 4(y coordinate))(1,4)

#2 (line#1) y=3x-1
(line#2) 2x+y=14
2x+(3x-1)=14
5x-1=14
5x=15
x=3
y=3(3)-1
y=9-1
y=8
(3,8)

#3 line#1 2x+3y=8
line#2 6x+9y=24
2x=8-3y
x=(8-3y)/2
6((8-3y)/2)+9y=24
24-9y+9y=24
24=24
(those two lines are on top of yeach other/the same line)
any point on the line

#4 line#1 3x-4y=12
line#2 y=3/4x-4
3x-4(3/4x-4)=12
3x-3x+16=12
16=12
parallel lines: lines with same slope and different y-intercept
No solution/they never intercept each other

I hope it is helpful, if you have any question, I will answer ASAP

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3 years ago

Nine cards are numbered from 1 to 9 and placed in a box. One card is selected at random and not replaced. Another card is random

gizmo_the_mogwai [7]

Answer:

1/6

Step-by-step explanation:

There are 4 primes. So the probability for the first draw is 4/9. Since the card is not replaced, the second probability is 3/8. 3/8 * 4/9 is 12/72, which simplifies into 1/6.

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