1 inch : 12feet. if the actual width of the tent is 36 feet how wide is the tent.
1 answer:
Answer:
If the actual width is 36 feet, then the tent is 3 inches wide in scale.
Step-by-step explanation:
Let x be the width in inches.
The scale is: 1 inch : 12feet. The scale can be represented as inches to feet ratio and then equivalent ratios will be used
This can be expressed as fraction as 1/12
The equivalent ratios are:
Hence,
If the actual width is 36 feet, then the tent is 3 inches wide in scale.
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Take the derivitive
f'(x)=3x^2+12x
find where it equals zero
it equal zero at x=0 and x=-4
find the y values
f(0)=-36
f(-4)=-4
the critical points are (0,-36) and (-4,-4)
make sign chart
evalutat f'(x) at x=-5 and x=-1 and x=1, and see their signs
f'(-5)=(+)
f'(-1)=(-)
f'(1)=(+)
see below attachment
max is where sign changes from (+) to (-)
min is where sign changes from (-) to (+)
so
max at (-4,-4)
min at (0,-36)
none of the options are correct, do you have te right problem?
f'(x)=3x^2+12x
find where it equals zero
it equal zero at x=0 and x=-4
find the y values
f(0)=-36
f(-4)=-4
the critical points are (0,-36) and (-4,-4)
make sign chart
evalutat f'(x) at x=-5 and x=-1 and x=1, and see their signs
f'(-5)=(+)
f'(-1)=(-)
f'(1)=(+)
see below attachment
max is where sign changes from (+) to (-)
min is where sign changes from (-) to (+)
so
max at (-4,-4)
min at (0,-36)
none of the options are correct, do you have te right problem?
Answer:
(a) 0.00000221 (b) 4.2 x
Step-by-step explanation:
(a) means you need to move the decimal left (because of the negative) 6 spaces. So you have 2.21 move the decimal 6 spaces left and you end up with 0.00000221
(b) If you have 420,000 and you count 5 spaces from the last number, that leaves the decimal inbetween the 4 and 2 so your answer will be 4.2 x