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Nat2105 [25]
3 years ago
10

Why is it essential to know how to solve Exponential equations in order to solve Logarithmic equations? (Make sure to fully expl

ain).
Mathematics
1 answer:
PtichkaEL [24]3 years ago
8 0

Answer:

Because you need it for your later life and for your GCSES and if you dont want to fail then you will need it.

Step-by-step explanation:

Given an exponential equation in which a common base cannot be found, solve for the unknown. Apply the logarithm of both sides of the equation. If one of the terms in the equation has base 10, use the common logarithm. If none of the terms in the equation has base 10, use the natural logarithm.

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Graph a triangle (STU) and reflect it over the y-axis to create triangle ST'U'.
lukranit [14]

The x-coordinates of \triangle S'T'U' will be the negation of the x-coordinates of \triangle STU

The line segment from S to the y-axis equals the line segment from S' to the y-axis. Similarly, the line segment from T to the y-axis equals the line segment from T' to the y-axis

See attachment for \triangle STU and \triangle S'T'U'

In order to solve this question, I will make the following assumptions.

Assume that the coordinates of \triangle STU are

S = (4,5)      

T = (5,9)

U=(3,8)

Refer to attachment for illustrations

<u>(1) Reflect </u>\triangle STU<u> over y-axis and describe the transformation</u>

To reflect \triangle STU across the y-axis, the following rule must be followed

(x,y) \to (-x,y)

This means that:

S = (4,5) \to S' = (-4,5)

T = (5,9) \to T' = (-5,9)

U=(3,8) \to U'=(-3,8)

<u>The description of the </u><u>transformation </u><u>is as follows:</u>

Notice that the signs of the x-coordinates \triangle STU and \triangle S'T'U' of both triangles are different.

In other words, if the x-coordinate of one is positive, then the other will have a negative x-coordinate; and vice versa.

<u>(2) Compare the segments and the line of reflection</u>

To reflect across the y-axis means that the reflecting line is the y-axis, itself.

The distance between a point to the y-axis is the absolute value of the x-coordinate.

So, the distance between S and the y-axis is:

S = |4| = 4

The distance between S' and the y-axis is:

S' = |-4| = 4

We can conclude that the two line segments are equal.

This is the same for other point T and T' because of the formula used above.

<u>From T and T' to the y-axis is:</u>

T =|5| =5

T' =|-5| =5

Read more at:

brainly.com/question/938117

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What fraction of one minute is 23 seconds
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There is 60 seconds in a minute so...

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Simplify -5-√-44<br><br> i have no idea
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Answer:

Undefined

Step-by-step explanation:

The square root of a negative number does not exist in the set of real numbers so it would be Undefined

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0.06 is ten times as much as what's
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.006, hope that helps, multiplying or dividing by ten you can just move the decimal point
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