Answer:
6
Step-by-step explanation:
STEP
1
:
1
Simplify —
3
The equation at the end of step
1
:
12 1
—— + (((—)2) • 9) • 3)
4 3
STEP
2
:
Equation at the end of step
2
:
12 1
—— + ((—— • 9) • 3)
4 32
STEP
3
:
Canceling Out:
3.1 Canceling out 32 as it appears on both sides of the fraction line
Equation at the end of step
3
:
12
—— + (1 • 3)
4
STEP
4
:
3
Simplify —
1
Equation at the end of step
4
:
3 + 3
STEP
5
:
Pulling out like terms
5.1 Pull out 3
After pulling out, we are left with :
3 • ( 1 - (-1) ))
Final result :
6
Answer:
I think the answer is 1
Step-by-step explanation:
-(-2)-1
=1
THE WHOLE THING???? or just one answer?
Answer:
hi
<u>Option C</u> will be your answer
Step-by-step explanation:
have a nice day!!
Answer:
Step-by-step explanation:
The position of an object moving horizontally after t seconds is given by the function
s = 3t - t³
a) The object is stationary when there is no external force acting on the body. When the body is at rest, the body remains in a position and here is no distance covered by the object i.e s = 0
b) velocity is the change in displacement of a body with respect to time.
v = ds/dt
S = 3t - t³
V = ds/dt = 3-3t²
at t = 2
Velocity = 3-3(2)²
Velocity = 3-12
Velocity = -9m/s
c) acceleration is the change in velocity of a body with respect to time.
acceleration = dv/dt
If v = 3-3t²
a = dv/dt = -6t
When v = 0
0 = 3-3t²
-3 = -3t²
t² = 1
t = ±√1
t = 1sec
The acceleration of the object at v = 0 occurs at t = 1sec and -1sec
a = -6(1)
a = -6m/s²
d) Given the speed of the body v modelled by the function
v = 3-3t²
The speed is decreasing when it is less than zero as shown:
3-3t²< 0
3<3t²
1<t²
±1<t
1<t and -1<t
t>±1
t >1 and t>-1
The speed is decreasing when
3-3t²<0 and t>1 or t>-1
