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Sedaia [141]
3 years ago
7

9 + 7 × ( 15 + 3 )÷3 2= Giving brainliest

Mathematics
1 answer:
xeze [42]3 years ago
3 0

Answer: 207 over 16 or in decimal form 12.9375

Step by step explanation:

Add 15 and 3 to get 18

9+ 7x18 over 32

Multiply the 7 and 18 to get 126

9+ 126 over 32

Reduce the fraction 126 over 32 to get the lowest terms by extracting and cancelling out the 2

9+ 63 over16

Convert 9 into the fraction 144 over 16

144over16 +63over16

Both of the fractions have the same denominator, therefore you should add them by using their numerators.

144+16over16

Add 144 and 63 to get the final number.

207over16

HOPE THIS HELPED YOU OUT, MATE! IF NOT THEN I'M SORRY!

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Let h(x)=20e^kx where k ɛ R (Picture attached. Thank you so much!)
zloy xaker [14]

Answer:

A)

k=0

B)

\displaystyle \begin{aligned} 2k + 1& = 2\ln 20 + 1 \\ &\approx 2.3863\end{aligned}

C)

\displaystyle \begin{aligned} k - 3&= \ln \frac{1}{2} - 3 \\ &\approx-3.6931 \end{aligned}

Step-by-step explanation:

We are given the function:

\displaystyle h(x) = 20e^{kx} \text{ where } k \in \mathbb{R}

A)

Given that h(1) = 20, we want to find <em>k</em>.

h(1) = 20 means that <em>h</em>(x) = 20 when <em>x</em> = 1. Substitute:

\displaystyle (20) = 20e^{k(1)}

Simplify:

1= e^k

Anything raised to zero (except for zero) is one. Therefore:

k=0

B)

Given that h(1) = 40, we want to find 2<em>k</em> + 1.

Likewise, this means that <em>h</em>(x) = 40 when <em>x</em> = 1. Substitute:

\displaystyle (40) = 20e^{k(1)}

Simplify:

\displaystyle 2 = e^{k}

We can take the natural log of both sides:

\displaystyle \ln 2 = \underbrace{k\ln e}_{\ln a^b = b\ln a}

By definition, ln(e) = 1. Hence:

\displaystyle k = \ln 2

Therefore:

2k+1 = 2\ln 2+ 1 \approx 2.3863

C)

Given that h(1) = 10, we want to find <em>k</em> - 3.

Again, this meas that <em>h</em>(x) = 10 when <em>x</em> = 1. Substitute:

\displaystyle (10) = 20e^{k(1)}

Simplfy:

\displaystyle \frac{1}{2} = e^k

Take the natural log of both sides:

\displaystyle \ln \frac{1}{2} = k\ln e

Therefore:

\displaystyle k = \ln \frac{1}{2}

Therefore:

\displaystyle k - 3 = \ln\frac{1}{2} - 3\approx-3.6931

3 0
3 years ago
Estimate by rounding each number to the nearest hundredth and then subtract 360.727 - 89.852
kykrilka [37]
Hi there!

The correct answer for you is 270.88.

To round to the hundreth's place (.0<u>1</u><u />), you need to take the number in the thousand's place (.00<u>1</u>), and determine if the number needs to go up or down.

If the number in the thousand's place is <u>greater</u> than 4, then the number goes up.

360.72<u>7</u> --> This means that the hundreth's number goes up to 3.

If the number in the thousand's place is <u>lesser</u> than 5, then that number stays the same.

89.85<u>2</u> --> This means that the hundreth's number stays the same.

After you round, then just subtract:

360.73 - 89.85 = 270.88.

I hope this helps!
Brady
<u />

7 0
3 years ago
Helpppp plssssss and thxxx
velikii [3]

Answer:

x ≤ 13

Step-by-step explanation:

hope this helps

5 0
3 years ago
Read 2 more answers
Which is the last operation performed when evaluating (8-2x)+4
jek_recluse [69]
Short Answer: Combine like terms
Remark

Just from what I see here, remove the brackets first and combine like terms second.

Discussion
8 - 2x + 4     The like therms are 8 and 4 First step
12 - 2x          That's the answer. Don't go any further. 2nd and last step



3 0
3 years ago
4sin^2 + 13cos^2 = 7. Find cos <br><br> Please read the picture question carefully and help !!
Vanyuwa [196]
4 sin^2 θ + 13cos^2 θ = 7
sin^2 θ = 1 - cos^ θ
4 - 4cos^2 θ + 13cos^2 θ = 7
9cos^2 θ = 3
cos^2 θ = 1/3
cos θ = # (1/3) # - square root
Square root of (1/3) has +1/3 and -1/3 as values of cos
Find the key angle by doing the cos inverse of #1/3
K.A = cos^-1 #(1/3) = 0.955
θ lies in all 4 quadrants
The values of θ are:
θ = 0.955, 2.186, 4.096, 7.23
Ignore 0.955, 2.186, 4.096, 7.23 as they are out of range pi/2 = 1.571
The the value of θ = 0.955 = 0.96 (to 2 d.p) radian

Hope it helped!
5 0
3 years ago
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