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3 years ago

How to show my work when I have a math problem

Mathematics

1 answer:

Over [174]3 years ago

5 0

Answer:

Here is how

Step-by-step explanation:

You find your answer to the problem and explain how do did it or you write the steps of how you did the problem. Also put your answer.

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Write an equation that represents the line. (-3,-6) and (2,-2) use exact numbers

Ilia_Sergeevich [38]

Given:

The line passes through (-3,-6) and (2,-2).

To find:

The equation of line.

Solution:

If a line passes through two points $(x_1,y_1)\text{ and }(x_2,y_2)$ , then the equation of line is

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

The line passes through (-3,-6) and (2,-2). So, the equation of line is

$y-(-6)=\dfrac{-2-(-6)}{2-(-3)}(x-(-3))$

$y+6=\dfrac{-2+6}{2+3}(x+3)$

$y+6=\dfrac{4}{5}(x+3)$

$y+6=\dfrac{4}{5}(x)+\dfrac{4}{5}(3)$

Subtract 6 from both sides.

$y=\dfrac{4}{5}(x)+\dfrac{12}{5}-6$

$y=\dfrac{4}{5}(x)+\dfrac{12-30}{5}$

$y=\dfrac{4}{5}(x)+\dfrac{-18}{5}$

$y=\dfrac{4}{5}(x)-\dfrac{18}{5}$

Therefore, the equation of line is $y=\dfrac{4}{5}(x)-\dfrac{18}{5}$ .

3 0

3 years ago

Help due in 45 minutes!!

Nat2105 [25]

Answer:

(14,-1)

Step-by-step explanation:

okay so first you need to use the "x=4y+10" in the first equation.

Rewrite as

3(4y+10) +11y=7

Distribute the 3(4y+10)

Rewrite as

12y+30

You'll have the equation

12y +30 +11y= 7

Subtract the 7 from both sides

12y+30+11y-7= 0

Combine like terms

23y+23=0

the best thing to do here is divide the equation by 23.

23/23 = 1

you'll have

y + 1 = 0

this simplifies to

y= -1

use this y value to solve for x

the easiest way to do this is start with the equation

x = 4y +10

Substitute the y for -1

x = -4(-1) +10

x = 4 +10

x = 14

the solution point is

(14,-1)

3 0

3 years ago

What is the Quotient of 1 and 2/3 divided by 2 and 3/5

Nostrana [21]

Answer:

25/39

Step-by-step explanation:

For division of mixed numbers, it often works well to first convert them to improper fractions. Then the division proceeds in the usual way: "invert and multiply", or "dot, swap."

$1\dfrac{2}{3}\div2\dfrac{3}{5}=\dfrac{5}{3}\div\dfrac{13}{5}=\dfrac{5}{3}\cdot\dfrac{5}{13}\\\\=\dfrac{5\cdot5}{3\cdot13}=\boxed{\dfrac{25}{39}}$

_____

<em>Additional comment</em>

Your graphing calculator can do this, too.

7 0

2 years ago

What is the percent of decrease of 90 to 72

vodomira [7]

You lose 20%.

if it were going up to 72 to 90 it would be a 25% increase

4 0

3 years ago

Read 2 more answers

If a vertical line is dropped from the x-axis to the point (12, –9) in the diagram below, what is the value of sec?

dem82 [27]

Answer:

Value of $\sec \theta = \frac{5}{4}$

Step-by-step explanation:

Given: A vertical line is dropped from the x-axis to the point (12, -9) as shown in the diagram below;

To find the value of $\sec \theta$ .

By definition of secants;

$\sec \theta = \frac{1}{\cos \theta}$

Now, first find the cosine of angle $\theta$

As the point (12 , -9) lies in the IV quadrant , where $\cos \theta > 0$

Consider a right angle triangle;

here, Adjacent side = 12 units and Opposite side = -9 units

Using Pythagoras theorem;

$(Hypotenuse side)^2= (12)^2 + (-9)^2 = 144 + 81 = 225$

$Hypotenuse = \sqrt{225} =15 units$

Cosine ratio is defined as in a right angle triangle, the ratio of adjacent side to hypotenuse side.

$\cos \theta = \frac{Adjacent side}{Hypotenuse side}$

then;

$\cos \theta = \frac{12}{15} = \frac{4}{5}$

and

$\sec \theta = \frac{1}{\cos \theta}= \frac{1}{\frac{4}{5}} = \frac{5}{4}$

therefore, the value of $\sec \theta$ is, $\frac{5}{4}$

5 0

3 years ago

Read 2 more answers