That's what it will look like
Start by writing the system down, I will use
to represent 

Substitute the fact that
into the first equation to get,

Simplify into a quadratic form (
),

Now you can use Vieta's rule which states that any quadratic equation can be written in the following form,

which then must factor into

And the solutions will be
.
Clearly for small coefficients like ours
, this is very easy to figure out. To get 5 and 6 we simply say that
.
This fits the definition as
and
.
So as mentioned, solutions will equal to
but these are just x-values in the solution pairs of a form
.
To get y-values we must substitute 3 for x in the original equation and then also 2 for x in the original equation. Luckily we already know that substituting either of the two numbers yields a zero.
So the solution pairs are
and
.
Hope this helps :)
4.5 cups to ounces is 36 fluid ounces.
Answer:
3.47 and 3.21
Step-by-step explanation:
Let us assume the nails length be X

Value let separated the top 3% is T and for bottom it would be B

Now converting, we get

Based on the normal standard tables, we get

Now compare these two above equations

So for top 3% it is 3.47
Now for bottom we applied the same method as shown above

Based on the normal standard tables, we get

Now compare these two above equations


hence, for bottom it would be 3.21
Answer:
4.56
Step-by-step explanation:
"Ordinary" interest will be more than "exact" interest because the number of days in a year is a smaller value. The difference will be ...
Io = Prt = 5000(0.12)(200/360) = 333.33
Ie = Prt = 5000(0.12)(200/365) = 328.77
The difference is ...
333.33 -328.77 = 4.56 . . . the difference in interest values
_____
<em>Additional comment</em>
The question asks for the difference between exact and ordinary interest, so the result is technically negative:
328.77 -333.33 = -4.56