Answer:
We need a sample size of least 119
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
The margin of error is:
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
Sample size needed
At least n, in which n is found when 
We don't know the proportion, so we use 
, which is when we would need the largest sample size.
Rounding up
We need a sample size of least 119
Step-by-step explanation:
Refer to attachment.
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em>
Answer:
$904,510.28
Step-by-step explanation:
If we assume the withdrawals are at the beginning of the month, we can use the annuity-due formula.
P = A(1 +r/n)(1 -(1 +r/n)^(-nt))/(r/n)
where r is the APR, n is the number of times interest is compounded per year (12), A is the amount withdrawn, and t is the number of years.
Filling in your values, we have ...
P = $4000(1 +.034/12)(1 -(1 +.034/12)^(-12·30))/(.034/12)
P = $904,510.28
You need to have $904,510.28 in your account when you begin withdrawals.
-1(4x-3)-5x+2
-4x+3-5x+2
-9x+6
i just simplified it. was there supposed to be more to this problem or is thins what you wanted?
