According to the identity if a+b+c=0
then a3+b3+c3=3abc
a3+b3+c3/abc=3
a2*a/bc*a+b2*b/ca*b+c2*c/ab*c=3
cancel a,b,c in all the fraction then you get
<span>a²/bc+b²/ca+c²/ab=3.
</span>hence proved
Answer:
1,5
Step-by-step explanation:
Y=1/3[-3]-2 I think is the answer
Answer: Exact form: 6/5 Decimal form: 1.2 Mixed Number form: 1 1/5
hope this helps! :)
Answer:
The table will be:
x |-2 | -1 | 0 | 1 | 2
y | 1 | 4 | 5 | 4 | 2
Step-by-step explanation:
The function is:

a) The x values of the table is:
x |-2 | -1 | 0 | 1 | 2
So, when x = -2, y will be:

Doing the same with the other x values we have:




The table will be:
x |-2 | -1 | 0 | 1 | 2
y | 1 | 4 | 5 | 4 | 1
I hope it helps you!