Complete question:
The growth of a city is described by the population function p(t) = P0e^kt where P0 is the initial population of the city, t is the time in years, and k is a constant. If the population of the city atis 19,000 and the population of the city atis 23,000, which is the nearest approximation to the population of the city at
Answer:
27,800
Step-by-step explanation:
We need to obtain the initial population(P0) and constant value (k)
Population function : p(t) = P0e^kt
At t = 0, population = 19,000
19,000 = P0e^(k*0)
19,000 = P0 * e^0
19000 = P0 * 1
19000 = P0
Hence, initial population = 19,000
At t = 3; population = 23,000
23,000 = 19000e^(k*3)
23000 = 19000 * e^3k
e^3k = 23000/ 19000
e^3k = 1.2105263
Take the ln
3k = ln(1.2105263)
k = 0.1910552 / 3
k = 0.0636850
At t = 6
p(t) = P0e^kt
p(6) = 19000 * e^(0.0636850 * 6)
P(6) = 19000 * e^0.3821104
P(6) = 19000 * 1.4653739
P(6) = 27842.104
27,800 ( nearest whole number)
Answer:
its just a black screeeeen
Step-by-step explanation:
We have to convert the measurements
the tray is 60 cm by 50 cm
if the cake tin is 25 cm in diameter, it will fit just 4 cakes because we have a length of 60 cm (will have 10 cm left over) and a width of 50 cm
hope it helps
Answer:
-7.8k - 7.2
Step-by-step explanation:
Distribute 0.6 to the terms in the parentheses:
0.6(-13k - 12)
-7.8k - 7.2
So, the simplified expression is -7.8k - 7.2
Answer:
Ano bayan puro Math nalang nakikita ko
