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Inga [223]
3 years ago
5

On Friday,a museum had 185 visitors. On Saturday,there were twice as many visitors as Friday. On Sunday,50 fewer people visited

the museum than Saturday.How many people visited the museum during these three days?
Mathematics
2 answers:
kaheart [24]3 years ago
6 0
Friday-185
Saturday-370
Sunday-320
The museum earned a total of $875
RoseWind [281]3 years ago
3 0
Friday - 185

Saturday - 185 x 2
= 370

Sunday - 370 - 50
= 320
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Joe spends $8 on lunch and 6.50 on dry cleaning.He also buys 2 shirts that cost the same amount. Joe spends a total of $52.What
emmainna [20.7K]
52-8=44
44-6.50=37.50
37.50/2=18.75
18.75 per shirt
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3 years ago
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Help please this is a quiz
aleksley [76]

Answer:

x^3 - 3x^2 +2x

Step-by-step explanation:

Use the distributive property

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2 years ago
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If you help me I’ll mark brainliest
Ivahew [28]

Answer:

∠2=92°

Step-by-step explanation:

Using an angle formula, -8x+144=2x+74

Simplification:

-8x+144=2x+74

-8x+70=2x

70=10x

x=7

Therefore, each angle is 88°

Now, because ∠2 is adjacent to one of 88°, they add up to 180°

Therefore,

180°=88°+∠2

∠2=92°

7 0
2 years ago
SEE ATTACHED
fenix001 [56]
To me personally, the first bit f(g(x)) is easy and the domain is tricky. Let's try explain this.

A function takes an input number and returns an output number depending on the function. Look at f(x) = x+3, if we let the input number be 2 then we say that f(2) = 5. We could do f(π) to give us π+3 or even f(x²) to give us x² +3. The trick is to substitute the input into the function equation.

You have been asked to find f(g(x)). You know f(x) = \frac{1+x}{1-x}. Putting numbers in at this point would be easy (try work out f(2), you'll do it really quick) but you have to put in g(x).

f(g(x)) = \frac{1+g(x)}{1-g(x)}
we also know that g(x) = \frac{x}{1-x} so we can say that
f(g(x)) = \frac{1+ \frac{x}{1-x} }{1- \frac{x}{1-x} } and that is f(g(x)) but the question requires that we simplify it so
\frac{1+ \frac{x}{1-x} }{1- \frac{x}{1-x} }  =  \frac{ \frac{1-x}{1-x} +  \frac{x}{1-x} }{ \frac{1-x}{1-x} - \frac{x}{1-x} } =  \frac{ \frac{1}{1-x} }{ \frac{1-2x}{1-x} } =  \frac{1}{1-2x}

f(g(x)) = \frac{1}{1-2x}

Now for the tricky bit (for me, at least). The domain is the full set of values that you can 'put in to' the function and still get a real value out. So how do we work out what numbers 'break' the function? I like to use the fact that DIVIDING BY ZERO IS IMPOSSIBLE. What value of x can we put into the function to make it so the function is being divided by 0? i.e. 1-2x = 0 solve that and you have a value of x that isn't part of the domain.

This means the domain is all real numbers EXCEPT the solution to that equation. (Because if we put that value into f(g(x)) it's impossible to get a value out.)

[I know this was a lot to read, if you have any questions or don't get anything feel free to message me or leave a comment.]

5 0
3 years ago
Log 15 (2x − 2) = log 15 (x+9)
notka56 [123]

Answer:

x=11

Step-by-step explanation:

Given the equation

\log_{15}(2x-2)=\log_{15}(x+9)

Note that

2x-2>0\\ \\2x>2\\ \\x>1

and

x+9>0\\ \\x>-9

Combined, x>1

Solve the equation:

2x-2= x+9\\ \\2x-x=9+2\\ \\x=11

Since 11>1, this is the solution to the equation.

5 0
3 years ago
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