Question

Can someone show me the steps to solving this (Rationalizing Denominator)

Answer 1

Answer:

$\huge \purple {\frac{2 \sqrt[3]{6} + \sqrt[3]{18} }{ 6} }$

Step-by-step Explanation:

$\huge \frac{2 + \sqrt[3]{3} }{ \sqrt[3]{6} } \\ \\ = \huge \frac{(2 + \sqrt[3]{3} )}{ \sqrt[3]{6} } \times \frac{ \sqrt[3]{6} \times \sqrt[3]{6} }{\sqrt[3]{6} \times \sqrt[3]{6}} \\ \\ = \huge \frac{(2 + \sqrt[3]{3} )}{ \sqrt[3]{6} } \times \frac{ \sqrt[3]{6 ^{2} } }{\sqrt[3]{6^{2}} } \\ \\ = \huge \frac{(2 + \sqrt[3]{3} )\sqrt[3]{6} }{ \sqrt[3]{6} \times \sqrt[3]{6 ^{2} }} \\ \\ = \huge \frac{(2 \sqrt[3]{6} + \sqrt[3]{3} \sqrt[3]{6} )}{ \sqrt[3]{6 ^{3} }} \\ \\ = \huge \orange{\frac{2 \sqrt[3]{6} + \sqrt[3]{18} }{ 6} }$