A pair of parallel lines is cut by a transversal, as shown:

1 answer:

8 0

<h3>Answer:</h3><h3 /><h2>Step-by-step explanation: the answer</h2><h2>let p' be the corresponding angle of the angle p (that is because of the prallelism and the transversal, look the image)</h2><h2>but p' and p are correspondant angles implies p'=p,</h2><h2>looking at the figure, p' and q are opposite angles</h2><h2>so q=p' and p'=p implies q=p</h2><h2>the answer is</h2><h2>p = q</h2><h2 />

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Answer:

Part A:

Since the slopes of the lines are not equal, the pair of equations for lines A and B will have one solution.

Part B:

(3 ,5 ) is the solution to the equations of lines A and B.

Step-by-step explanation:

Part A:

We are required to determine the number of solutions that the pair of equations for lines A and B have. To do this, we shall determine the slope of each line;

A straight line labeled A joins the ordered pair 2, 6 with the ordered pair 6, 2. The slope is defined as;

(change in y) / (change in x)

The slope of line A is thus;

(2 - 6)/(6 - 2) = -1

A straight line B joins the ordered pair 0, 3 with the ordered pair 4.5, 6.

On the other hand, the slope of line B is;

(6 - 3) / (4.5 - 0) = 2/3

Since the slopes of the lines are not equal, the pair of equations for lines A and B will have one solution.

Part B:

What is the solution to the equations of lines A and B?

We first need to determine the equation of each line;

Line A, the slope was found to be -1 and the line passes through (2,6)

The equation of the line in slope intercept form is;

y = -x + c

6 = -2 + c

c = 8

y = -x + 8

On the other hand, the slope of line B was found to be 2/3 and the line passes through (0,3). Therefore, we have;

y = 2/3x + c

3 = 2/3 (0) + c

c= 3

y = (2/3)x + 3

The graph of these two lines is shown in the attachment below. The lines intersect at (3 ,5 ) which is the solution to the equations of lines A and B.

The graphical solution to a system of linear equations is given by the point of intersection of the two lines representing each equation.