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3 years ago

A pair of parallel lines is cut by a transversal, as shown:

1 answer:

8 0

<h3>Answer:</h3><h3 /><h2>Step-by-step explanation: the answer</h2><h2>let p' be the corresponding angle of the angle p (that is because of the prallelism and the transversal, look the image)</h2><h2>but p' and p are correspondant angles implies p'=p,</h2><h2>looking at the figure, p' and q are opposite angles</h2><h2>so q=p' and p'=p implies q=p</h2><h2>the answer is</h2><h2>p = q</h2><h2 />

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Calculate the sample standard deviation and sample variance for the following frequency distribution of hourly wages for a sampl

lidiya [134]

Answer:

(a) The sample variance is 16.51

(a) The sample standard deviation is 4.06

Step-by-step explanation:

Given

$\begin{array}{cc}{Class} & {Frequency} & 8.26 - 10.00 & 20 &10.01-11.75 & 38 &11.76 - 13.50& 36 & 13.51-15.25 &25&15.26-17.00 &27 &\ \end{array}$

Solving (a); The sample variance.

First, calculate the class midpoints.

This is the mean of the intervals.

i.e.

$x_1 = \frac{8.26+10.00}{2} = \frac{18.26}{2} = 9.13$

$x_2 = \frac{10.01+11.75}{2} = \frac{21.76}{2} = 10.88$

$x_3 = \frac{11.76+13.50}{2} = \frac{25.26}{2} = 12.63$

$x_4 = \frac{13.51+15.25}{2} = \frac{28.76}{2} = 14.38$

$x_5 = \frac{15.26+17.00}{2} = \frac{32.26}{2} = 16.13$

So, the table becomes:

$\begin{array}{ccc}{Class} & {Frequency} & {x} & 8.26 - 10.00 & 20&9.13 &10.01-11.75 & 38 &10.88&11.76 - 13.50& 36 &12.63& 13.51-15.25 &25&14.38&15.26-17.00 &27 &16.13\ \end{array}$

Next, calculate the mean

$\bar x = \frac{\sum fx}{\sum f}$

$\bar x = \frac{20*9.13 + 38 * 10.88+36*12.63+25*14.38+27*16.13}{20+38+36+25+27}$

$\bar x = \frac{1845.73}{146}$

$\bar x = 12.64$

Next, the sample variance is:

$\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f - 1}$

So, we have:

$\sigma^2 = \frac{20*(9.13-12.63)^2 + 38 * (10.88-12.63)^2 +...........+27 * (16.13 -12.63)^2}{20+38+36+25+27-1}$

$\sigma^2 = \frac{2393.6875}{145}$

$\sigma^2 = 16.51$

The sample standard deviation is:

$\sigma = \sqrt{\sigma^2}$

$\sigma = \sqrt{16.51}$

$\sigma = 4.06$

6 0

3 years ago

 −   −      =<br>    <br> 10 8

san4es73 [151]

Answer:

ANSWER might be 6

Hope it helps

3 0

2 years ago

-2 with a exponent six

DIA [1.3K]

$-2^{6} 

$ = -2 with a exponent six
Well Exponents mean that you multiply the number 6 times.
Soo..
$-2^{6}$ = -2 x -2 x -2 x -2 x -2 x -2 = 64

So <span> $-2^{6}$ = 64
</span>
Good Luck! :)

5 0

3 years ago

Read 2 more answers

Write the denominator of the fractiona 7/20 as the product of prime factors

gtnhenbr [62]

Answer:

Step-by-step explanation:

prime factors of 20 = 2 * 2 * 5

$\frac{7}{20}=\frac{7}{2*2*5}$