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sveta [45]
3 years ago
12

How to solve: Sin(x)=x^2-pi^2

Mathematics
1 answer:
LiRa [457]3 years ago
6 0

Rewrite the equation as

\sin(x) = x^2-\pi^2 = (x-\pi)(x+\pi)

If we choose x=\pm\pi, the right hand side becomes zero, and so does the left hand side.

If you graph the two functions f(x) = \sin(x) and g(x) = x^2-\pi^2, you'll see that there are only two solutions, so the ones we found are the only ones.

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