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alukav5142 [94]
3 years ago
9

Two pounds of dried cranberries cost $5.04, 3 pounds of dried cranberries cost $7.56, and 7 pounds of dried cranberries cost $17

.64. What equation gives the total cost y of x pounds of dried cranberries?
Mathematics
1 answer:
MAVERICK [17]3 years ago
4 0

Answer:

y = 2.52x

y = cost, x = pounds of cranberries.

each pound costs 2.52

Step-by-step explanation:

5.04/2 = 2.52

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A rectangular school banner has a length of 36 inches and a width of 52 inches. A sign is made that is similar to the school ban
zalisa [80]

Answer:

<u>4212 : 1573</u> is the ratio.

Step-by-step explanation:

Given:

Length of rectangular school banner is 36 inches and width is 52 inches.

And, the sign made is similar to banner.

The sign's length is 22 inches.

Now, we have to find the ratio of the area of the banner to the area of the sign.

So, we have dimensions of rectangular school banner:

Length = 36 inches.

Width = 52 inches.

But, we have only length of sign:

Length = 22 inches.

Now, we have to find the width of sign by using cross multiplication method:

Let the width of sign be x.

<em>As, sign is similar to banner.</em>

So, if 36 inches is equivalent to 52 inches.

Then, 22 inches is equivalent to x.

\frac{36}{52} =\frac{22}{x}

<em>By cross multiplying we get:</em>

<em />36x=1144<em />

<em>Dividing both sides by 36 we get:</em>

x=31\frac{7}{9} .

<em>Hence, the width of sign is </em>31\frac{7}{9}<em> inches.</em>

Now, we find the area of banner and the area of sign by putting formula:

Area of banner = length × width.

Area\ of\ banner=36\times 52

Area\ of\ banner=1872\ square\ inches.

Now, area of sign:

Area\ of\ sign=length\times width\\\\Area\ of\ sign=22\times 31\frac{7}{9} \\\\Area\ of\ sign=22\times \frac{286}{9} \\\\Area\ of\ sign=\frac{6292}{9} \ square\ inches.

Now, to get the ratio of the area of the school banner to the area of the sign:

1872:\frac{6292}{9}

=\frac{1872}{\frac{6292}{9} } \\\\=\frac{16848}{6292}

<em>On simplifying we get:</em>

=\frac{4212}{1573}

=4212:1573.

Therefore, the ratio of the area of the school banner to the area of the sign is 4212:1573.

8 0
3 years ago
How many ounces of a silver alloy that cost $4 an ounce must be mixed with 10oz of an alloy that costs $6 an ounce to make a mix
scoray [572]

Answer:

x = 52.5

Step-by-step explanation:

4x + 6(10) = 4.32(x + 10)

4x + 60 = 4.32x + 43.20

0.32x = 16.8

x= 52.5

5 0
3 years ago
Find measure of angle BDC
Liula [17]
The 2 angles are complemantary or form right angles so -3x+20-2x+55=90=-5x+75=90=-5x=15&#10; sox=3. Plugging that into BDC we get 11
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3 years ago
Find the exact solution using common logarithms 2^5x+3= 3^2x+1
AfilCa [17]
2^{5x + 3} = 3^{2x + 1}
log_{2}(2^{5x + 3}) = log_{2}(3^{2x + 1})
(5x + 3)log_{2}(2) = (2x + 1)log_{2}(3)
5x + 3 = 1.58(2x + 1)
5x + 3 = 3.16x + 1.58
1.84x + 3 = 1.58
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4 years ago
Find the number that makes the ratio equivalent to 2:3.<br> 24: BLANK
Vitek1552 [10]

Answer:

equivalent ratio for this question is

4:6:48

5 0
2 years ago
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