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fenix001 [56]
3 years ago
7

A fair coin is tossed three times in succession. the set of equally likely outcomes is startset hhh comma hht comma hth comma th

h comma htt comma tht comma tth comma ttt endset. find the probability of getting exactly one head.
Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
5 0

Solution:

As Given a coin is tossed thrice.

Total possible outcome = {HHH, TTT,HHT,HTH,THH,TTH,THT,HTT}=8

Total Favorable outcome = Exactly one Head = {TTH, THT,HTT} = 3

Probability of getting exactly one head = \frac{\text{Total favorable outcome}}{\text{Total Possible Outcome}}

          = \frac{3}{8}

ArbitrLikvidat [17]3 years ago
3 0
If a fair coin is tossed three times, sample = 2^3 = 8 (hhh, hht, hth, thh, htt, tht, tth, ttt) where h=head and t=tail.

Probability of getting one:

Outcomes with one head (h) = 3

P(1 h) = 3/8 = 0.375
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<u>Answer:   </u>

Required linear equation to get number of pencils purchased by Casper is 3x – 45 = 0 where x represents number of pencils and number of pencils Casper purchased = 15.

<u>Solution: </u>

Let’s assume number of pencils purchased by Casper = x

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On solving the linear equation 3x – 45 = 0 for x we get

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