Question

A fair coin is tossed three times in succession. the set of equally likely outcomes is startset hhh comma hht comma hth comma thh comma htt comma tht comma tth comma ttt endset. find the probability of getting exactly one head.

Answer 1

Solution:

As Given a coin is tossed thrice.

Total possible outcome = {HHH, TTT,HHT,HTH,THH,TTH,THT,HTT}=8

Total Favorable outcome = Exactly one Head = {TTH, THT,HTT} = 3

Probability of getting exactly one head = $\frac{\text{Total favorable outcome}}{\text{Total Possible Outcome}}$

          = $\frac{3}{8}$

Answer 2

If a fair coin is tossed three times, sample = 2^3 = 8 (hhh, hht, hth, thh, htt, tht, tth, ttt) where h=head and t=tail.

Probability of getting one:

Outcomes with one head (h) = 3

P(1 h) = 3/8 = 0.375